if 语句将所有语句分组为一个 if 语句

Question

你如何制作一个 if 语句，将所有语句分组为一个 if 语句，目前我有 20 个或其他 if 语句，这不是很有效，所以我想知道是否有一种方法可以将精灵分组，以便如果我的任何精灵都会离开屏幕顶部，然后重新出现在底部，反之亦然。

目前我已经得到了这个； yellow1,2,3... 是这里的精灵

if (yellow1.position.y-33>=320) {
  yellow1.position = ccp(yellow1.position.x,33);
}
if (yellow1.position.y+33<=0) {
  yellow1.position = ccp(yellow1.position.x,287);
}
if (yellow2.position.y-33>=320) {
  yellow2.position = ccp(yellow2.position.x,33);
}
if (yellow2.position.y+33<=0) {
  yellow2.position = ccp(yellow2.position.x,287);
}
if (yellow3.position.y-33>=320) {
  yellow3.position = ccp(yellow3.position.x,33);
}
if (yellow3.position.y+33<=0) {
  yellow3.position = ccp(yellow3.position.x,287);
}
if (yellow4.position.y-33>=320) {
  yellow4.position = ccp(yellow4.position.x,33);
}
if (yellow4.position.y+33<=0) {
  yellow4.position = ccp(yellow4.position.x,287);
}
if (yellow5.position.y-33>=320) {
  yellow5.position = ccp(yellow5.position.x,33);
}
if (yellow5.position.y+33<=0) {
  yellow5.position = ccp(yellow5.position.x,287);
}
if (yellow6.position.y-33>=320) {
  yellow6.position = ccp(yellow6.position.x,33);
}
if (yellow6.position.y+33<=0) {
  yellow6.position = ccp(yellow6.position.x,287);
}
if (yellow7.position.y-33>=320) {
  yellow7.position = ccp(yellow7.position.x,33);
}
if (yellow7.position.y+33<=0) {
  yellow7.position = ccp(yellow7.position.x,287);
}
if (yellow8.position.y-33>=320) {
  yellow8.position = ccp(yellow8.position.x,33);
}
if (yellow8.position.y+33<=0) {
  yellow8.position = ccp(yellow8.position.x,287);
}

，这是我到目前为止的循环：

for (int i=0;i<16 ; i++) {
    if (((CCSprite *)[c1array objectAtIndex:i]).position.y-((CCSprite *)[c1array objectAtIndex:i]).contentSize.height>320) {
        ((CCSprite *)[c1array objectAtIndex:i]).position = ccp(((CCSprite *)[c1array objectAtIndex:i]).position.x,37);
    }
    if (((CCSprite *)[c1array objectAtIndex:i]).position.y+((CCSprite *)[c1array objectAtIndex:i]).contentSize.height<0) {
        ((CCSprite *)[c1array objectAtIndex:i]).position = ccp(((CCSprite *)[c1array objectAtIndex:i]).position.x,253);
    }
}

Answer 1

您可以将精灵放入数组列表中，然后循环遍历该列表。这意味着您正在运行相同数量的代码，但让运行时做它擅长的事情，您的代码将会更加整洁。

Answer 2

你想要的是一个循环。但首先，您需要将数据构建为顺序数据结构，例如数组。然后您将循环遍历数组中的每个元素。

我不熟悉 iPhone 编程，但这里是一般的伪代码：

// Create the list
const int SPRITE_COUNT = 8;
Sprite[] sprites = new Sprite[SPRITE_COUNT];
for(int i = 0; i < SPRITE_COUNT; ++i)
    sprites[i] = new Sprite();

// Later, check for sprites outside
for(int i = 0; i < SPRITE_COUNT; ++i)
{
    if ((sprites[i].position.y + 33) <= 0)
        ccp(sprite.position.x, 287);
    if ((sprites[i].position.y - 33) >= 320)
        ccp(sprite.position.x, 33);
}