Objc：使用不符合 RFC 2396 的字符串创建 NSURL
我遇到这种情况，我需要创建一个包含 " 的字符串的 URL。
例如：
NSString *myStringWithURL = [NSString stringWithFormat:
@"http://myurl.com/setParam.php?setName=
{\"name\":\"%@\"} ", name];
// myStringWithURL will return the desired URL but it is a String.
// of course I need it as URL in order to make the request.
NSURL *targetURL = [NSURL URLWithString : myStringWithURL];
//This will return nil.
所以问题是如何让我的 URL 不返回 nil？
{"name":"My Name"} 部分应该是JSON 但这似乎比使用 NSDictionary 然后使用 JSON 解析器等更简单，
非常感谢您的帮助！
I have this situation where I need to make a URL with a string that contains ".
For instance:
NSString *myStringWithURL = [NSString stringWithFormat:
@"http://myurl.com/setParam.php?setName=
{\"name\":\"%@\"} ", name];
// myStringWithURL will return the desired URL but it is a String.
// of course I need it as URL in order to make the request.
NSURL *targetURL = [NSURL URLWithString : myStringWithURL];
//This will return nil.
So the question is how to get my URL to not return nil?
The part {"name":"My Name"} should be a JSON but this seemed simpler than using a NSDictionary and then using the parser of JSON and so on.
I thank you very much for your help!!
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使用 stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding 转换字符串
use stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding to convert your string