realpath() 不解析符号链接?

发布于 2024-10-13 21:27:59 字数 186 浏览 4 评论 0原文

我已经读过有关 realpath() 的内容,但是是否有一个函数可以传递基本目录和文件名,可以在不解析符号链接或检查文件是否实际存在的情况下给出以下结果?或者我是否必须使用修改后的realpath()?

"/var/", "../etc///././/passwd" => "/etc/passwd"

I already read about realpath(), but is there a function that I can pass a base directory and a filename that would give me the following result without resolving symlinks or checking whether files actually exist? Or do I have to use a modified realpath()?

"/var/", "../etc///././/passwd" => "/etc/passwd"

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很酷不放纵 2024-10-20 21:27:59

这是一个 normalize_path() 函数:

如果给定路径是相对路径,则该函数首先在其前面添加当前工作目录。

然后处理特殊路径组件,如...或空组件,并返回结果。

对于 ..,如果有最后一个组件,则将其删除(/.. 将仅返回 /)。
对于 . 或空组件(双 /),这将被跳过。

该函数确保不会返回空路径(而是返回 /)。

#define _GNU_SOURCE /* memrchr() */

#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <limits.h>

char * normalize_path(const char * src, size_t src_len) {

        char * res;
        size_t res_len;

        const char * ptr = src;
        const char * end = &src[src_len];
        const char * next;

        if (src_len == 0 || src[0] != '/') {

                // relative path

                char pwd[PATH_MAX];
                size_t pwd_len;

                if (getcwd(pwd, sizeof(pwd)) == NULL) {
                        return NULL;
                }

                pwd_len = strlen(pwd);
                res = malloc(pwd_len + 1 + src_len + 1);
                memcpy(res, pwd, pwd_len);
                res_len = pwd_len;
        } else {
                res = malloc((src_len > 0 ? src_len : 1) + 1);
                res_len = 0;
        }

        for (ptr = src; ptr < end; ptr=next+1) {
                size_t len;
                next = memchr(ptr, '/', end-ptr);
                if (next == NULL) {
                        next = end;
                }
                len = next-ptr;
                switch(len) {
                case 2:
                        if (ptr[0] == '.' && ptr[1] == '.') {
                                const char * slash = memrchr(res, '/', res_len);
                                if (slash != NULL) {
                                        res_len = slash - res;
                                }
                                continue;
                        }
                        break;
                case 1:
                        if (ptr[0] == '.') {
                                continue;

                        }
                        break;
                case 0:
                        continue;
                }
                res[res_len++] = '/';
                memcpy(&res[res_len], ptr, len);
                res_len += len;
        }

        if (res_len == 0) {
                res[res_len++] = '/';
        }
        res[res_len] = '\0';
        return res;
}

Here is a normalize_path() function:

If the given path is relative, the function starts by prepending the current working directory to it.

Then the special path components like .., . or empty components are treated, and the result is returned.

For .., the last component is removed if there is one (/.. will just return /).
For . or empty components (double /), this is just skipped.

The function ensures to not return empty an path (/ is returned instead).

#define _GNU_SOURCE /* memrchr() */

#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <limits.h>

char * normalize_path(const char * src, size_t src_len) {

        char * res;
        size_t res_len;

        const char * ptr = src;
        const char * end = &src[src_len];
        const char * next;

        if (src_len == 0 || src[0] != '/') {

                // relative path

                char pwd[PATH_MAX];
                size_t pwd_len;

                if (getcwd(pwd, sizeof(pwd)) == NULL) {
                        return NULL;
                }

                pwd_len = strlen(pwd);
                res = malloc(pwd_len + 1 + src_len + 1);
                memcpy(res, pwd, pwd_len);
                res_len = pwd_len;
        } else {
                res = malloc((src_len > 0 ? src_len : 1) + 1);
                res_len = 0;
        }

        for (ptr = src; ptr < end; ptr=next+1) {
                size_t len;
                next = memchr(ptr, '/', end-ptr);
                if (next == NULL) {
                        next = end;
                }
                len = next-ptr;
                switch(len) {
                case 2:
                        if (ptr[0] == '.' && ptr[1] == '.') {
                                const char * slash = memrchr(res, '/', res_len);
                                if (slash != NULL) {
                                        res_len = slash - res;
                                }
                                continue;
                        }
                        break;
                case 1:
                        if (ptr[0] == '.') {
                                continue;

                        }
                        break;
                case 0:
                        continue;
                }
                res[res_len++] = '/';
                memcpy(&res[res_len], ptr, len);
                res_len += len;
        }

        if (res_len == 0) {
                res[res_len++] = '/';
        }
        res[res_len] = '\0';
        return res;
}
吹梦到西洲 2024-10-20 21:27:59
function normalize_path($path, $pwd = '/') {
        if (!isset($path[0]) || $path[0] !== '/') {
                $result = explode('/', getcwd());
        } else {
                $result = array('');
        }
        $parts = explode('/', $path);
        foreach($parts as $part) {
            if ($part === '' || $part == '.') {
                    continue;
            } if ($part == '..') {
                    array_pop($result);
            } else {
                    $result[] = $part;
            }
        }
        return implode('/', $result);
}

(在我写这篇文章时,这个问题被标记为 PHP。)

无论如何,这里是一个正则表达式版本:

function normalize_path($path, $pwd = '/') {
        if (!isset($path[0]) || $path[0] !== '/') {
                $path = "$pwd/$path";
        }
        return preg_replace('~
                ^(?P>sdotdot)?(?:(?P>sdot)*/\.\.)*
                |(?<sdotdot>(?:(?P>sdot)*/(?!\.\.)(?:[^/]+)(?P>sdotdot)?(?P>sdot)*/\.\.)+)
                |(?<sdot>/\.?(?=/|$))+
        ~sx', '', $path);
}
function normalize_path($path, $pwd = '/') {
        if (!isset($path[0]) || $path[0] !== '/') {
                $result = explode('/', getcwd());
        } else {
                $result = array('');
        }
        $parts = explode('/', $path);
        foreach($parts as $part) {
            if ($part === '' || $part == '.') {
                    continue;
            } if ($part == '..') {
                    array_pop($result);
            } else {
                    $result[] = $part;
            }
        }
        return implode('/', $result);
}

(The question was tagged PHP at the time I wrote this.)

Anyway, here is a regex version:

function normalize_path($path, $pwd = '/') {
        if (!isset($path[0]) || $path[0] !== '/') {
                $path = "$pwd/$path";
        }
        return preg_replace('~
                ^(?P>sdotdot)?(?:(?P>sdot)*/\.\.)*
                |(?<sdotdot>(?:(?P>sdot)*/(?!\.\.)(?:[^/]+)(?P>sdotdot)?(?P>sdot)*/\.\.)+)
                |(?<sdot>/\.?(?=/|$))+
        ~sx', '', $path);
}
合约呢 2024-10-20 21:27:59

我使用 Hardex解决方案

#include <string.h>

char * normalizePath(char* pwd, const char * src, char* res) {
    size_t res_len;
    size_t src_len = strlen(src);

    const char * ptr = src;
    const char * end = &src[src_len];
    const char * next;

    if (src_len == 0 || src[0] != '/') {
        // relative path
        size_t pwd_len;

        pwd_len = strlen(pwd);
        memcpy(res, pwd, pwd_len);
        res_len = pwd_len;
    } else {
        res_len = 0;
    }

    for (ptr = src; ptr < end; ptr=next+1) {
        size_t len;
        next = (char*)memchr(ptr, '/', end-ptr);
        if (next == NULL) {
            next = end;
        }
        len = next-ptr;
        switch(len) {
        case 2:
            if (ptr[0] == '.' && ptr[1] == '.') {
                const char * slash = (char*)memrchr(res, '/', res_len);
                if (slash != NULL) {
                    res_len = slash - res;
                }
                continue;
            }
            break;
        case 1:
            if (ptr[0] == '.') {
                continue;
            }
            break;
        case 0:
            continue;
        }

        if (res_len != 1)
            res[res_len++] = '/';

        memcpy(&res[res_len], ptr, len);
        res_len += len;
    }

    if (res_len == 0) {
        res[res_len++] = '/';
    }
    res[res_len] = '\0';
    return res;
}

示例:

#include <stdio.h>

int main(){
    char path[FILENAME_MAX+1];
    printf("\n%s\n",normalizePath((char*)"/usr/share/local/apps",(char*)"./../../../",path));
    return 0;
}

输出:

/usr


Note:

  1. 第一个参数是相对于其他路径将被规范化的目录路径(绝对路径)。一般是当前目录的绝对路径。
  2. 第二个参数是要在不解析符号链接的情况下规范化的字符串。
  3. 第三个参数是一个 char* ,它必须具有包含规范化路径所需的内存/容量。

I use Hardex's solution:

#include <string.h>

char * normalizePath(char* pwd, const char * src, char* res) {
    size_t res_len;
    size_t src_len = strlen(src);

    const char * ptr = src;
    const char * end = &src[src_len];
    const char * next;

    if (src_len == 0 || src[0] != '/') {
        // relative path
        size_t pwd_len;

        pwd_len = strlen(pwd);
        memcpy(res, pwd, pwd_len);
        res_len = pwd_len;
    } else {
        res_len = 0;
    }

    for (ptr = src; ptr < end; ptr=next+1) {
        size_t len;
        next = (char*)memchr(ptr, '/', end-ptr);
        if (next == NULL) {
            next = end;
        }
        len = next-ptr;
        switch(len) {
        case 2:
            if (ptr[0] == '.' && ptr[1] == '.') {
                const char * slash = (char*)memrchr(res, '/', res_len);
                if (slash != NULL) {
                    res_len = slash - res;
                }
                continue;
            }
            break;
        case 1:
            if (ptr[0] == '.') {
                continue;
            }
            break;
        case 0:
            continue;
        }

        if (res_len != 1)
            res[res_len++] = '/';

        memcpy(&res[res_len], ptr, len);
        res_len += len;
    }

    if (res_len == 0) {
        res[res_len++] = '/';
    }
    res[res_len] = '\0';
    return res;
}

Example:

#include <stdio.h>

int main(){
    char path[FILENAME_MAX+1];
    printf("\n%s\n",normalizePath((char*)"/usr/share/local/apps",(char*)"./../../../",path));
    return 0;
}

Output:

/usr


Note:

  1. The first argument is the directory path (absolute path) relative to which other paths will be normalized. It is generally the absolute path of the current directory.
  2. The second argument is the string to be normalized without resolving symlinks.
  3. The third argument is a char* which must have the required memory/capacity to contain the normalized path.
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