通过派生构造函数的参数初始化继承类 (C#)

发布于 2024-10-13 12:02:41 字数 352 浏览 6 评论 0原文

天啊，标题可能不是最好的，但我是一个相当新的程序员，对继承类没有太多经验。我正在尝试初始化一个类（我自己的 Stream 派生自普通 FileStream 类），并可以选择从派生的参数初始化基类。例如......

public class Example : FileStream
{
public Example(FileStream FS) : base = FS
}

显然我不能这样做，但它最好地展示了我想要做什么。我这样做的主要原因是因为流相互矛盾——我的意思是在这个类中，另一个类自动打开文件（并进行一些读取和诸如此类的操作），并且我抛出了一个异常文件无法访问。也许我做错了，但感谢大家的时间！

原文

Hell, the title probably wasn't the best, but I'm a fairly new programmer and haven't had much experience with inherited classes. I'm trying to initialize a class (my own Stream derived from the normal FileStream class) and have the option of initializing the base from the derived's arguments. For example...

public class Example : FileStream
{
public Example(FileStream FS) : base = FS
}

Obviously I can't just do that, but it best shows what I'd like to do. The main reason why I'm doing this is because of contradicting streams -- and what I mean by that is that within this class, another class automatically opens the file (and does some reading and whatnot) and I get thrown an exception that the file is inaccessible. Maybe I'm doing this wrong, but thanks for everyone's time!

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怀中猫帐中妖 2024-10-20 12:02:41

你不能那样做，不。但对于 Stream 具体来说，您可以从 Stream 派生，将 FileStream 存储在私有字段中并将所有方法调用传递给它：

public class Example : Stream
{
    private Stream _underlying;

    public Example(Stream underlying) { _underlying = underlying; }

    // Do the following for all the methods in Stream
    public override int Read(...) { return _underlying.Read(...); }
}

如果您将文本光标移动到Example :后面的Stream一词，按Alt+Shift+F10并选择“实现抽象类Stream”，它将生成所有方法声明你，但你仍然需要将所有抛出新的NotImplementedException()更改为对_underlying的正确调用。

You can’t do that, no. But for Stream specifically, you can derive from Stream, store the FileStream in a private field and pass all the method calls to it:

public class Example : Stream
{
    private Stream _underlying;

    public Example(Stream underlying) { _underlying = underlying; }

    // Do the following for all the methods in Stream
    public override int Read(...) { return _underlying.Read(...); }
}

If you move the text cursor to the word Stream after the Example :, press Alt+Shift+F10 and choose “Implement abstract class Stream”, it will generate all the method declarations for you, but you will still have to change all the throw new NotImplementedException() into the proper calls to _underlying.

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撞了怀 2024-10-20 12:02:41

正如您所预料的，您在语法中犯了错误，您可以
帮助这个例子。

public class SomeClassA
{
    public int foo1;
    public string foo2;
    public SomeClassA(int foo1, string foo2)
    {
        this.foo1 = foo1;
        this.foo2 = foo2;
    }
}
public class SomeClassB : SomeClassA
{
    public SomeClassB(int arg1, string arg2)
        : base(arg1, arg2)
    { }
}

As you might expected, you're making a mistake in the syntax, you can
help with this example.

public class SomeClassA
{
    public int foo1;
    public string foo2;
    public SomeClassA(int foo1, string foo2)
    {
        this.foo1 = foo1;
        this.foo2 = foo2;
    }
}
public class SomeClassB : SomeClassA
{
    public SomeClassB(int arg1, string arg2)
        : base(arg1, arg2)
    { }
}

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