WPF：获取子 UIElement 在其父级中的位置。忽略 RenderTransform（如果有）

发布于 2024-10-13 09:24:19 字数 1211 浏览 2 评论 0原文

假设我有以下 XAML 代码：

<DockPanel Name="pan">
    <Label Content="AAA" Name="lab1" />
    <Label Content="BBB" Name="lab2" />
    <Label Content="CCC" Name="lab3" />
</DockPanel>

我的代码背后是我想找出 pan 中 lab2 的坐标。然而我想忽略lab2任何存在的RenderTransform。因此，解决方案必须为上述代码和以下代码返回相同的坐标：

<DockPanel>
    <Label Content="AAA" />
    <Label Content="BBB" >
        <Label.RenderTransform>
            <TranslateTransform Y="20"/>
        </Label.RenderTransform>
    </Label>
    <Label Content="CCC" />
</DockPanel>

换句话说，我想要在调用 Arrange< 时由 pan 的 ArrangeOverride 方法设置的位置but2 上的 /code>。我将其称为“逻辑位置”。可以通过调用以下方法来获取“视觉位置”：

private Point visualPoss() {
    Point lab2Vis = lab2.PointToScreen(new Point(0, 0));
    Point panVis = pan.PointToScreen(new Point(0, 0));
    return new Point(lab2Vis.X - panVis.X, lab2Vis.Y - panVis.Y);
}

但这并不是我的问题的解决方案，因为对于上面的两个 XAML 代码示例，此 visualPoss() 的返回值并不相等。

如果有不清楚的地方请发表评论。

谢谢

原文

Lets say I have this XAML code:

<DockPanel Name="pan">
    <Label Content="AAA" Name="lab1" />
    <Label Content="BBB" Name="lab2" />
    <Label Content="CCC" Name="lab3" />
</DockPanel>

I my code behind I want to find out what are the coordinates of lab2 within pan. Hovewer I want to ignore any present RenderTransform of lab2. So the solution must return same coordinates for above code and following:

<DockPanel>
    <Label Content="AAA" />
    <Label Content="BBB" >
        <Label.RenderTransform>
            <TranslateTransform Y="20"/>
        </Label.RenderTransform>
    </Label>
    <Label Content="CCC" />
</DockPanel>

In another words I want the position that was set by the ArrangeOverride method of pan when calling Arrange on but2. I would call it 'logical position'. The 'visual position' can be obtained by calling following method:

private Point visualPoss() {
    Point lab2Vis = lab2.PointToScreen(new Point(0, 0));
    Point panVis = pan.PointToScreen(new Point(0, 0));
    return new Point(lab2Vis.X - panVis.X, lab2Vis.Y - panVis.Y);
}

But this is not a solution of my problem as the return value of this visualPoss() is not equal for both XAML code examples above.

Please leave comment if somehing is unclear.

Thank you

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扶醉桌前 2024-10-20 09:24:19

看起来有一个非常简单明了的解决方案：

private Point logicalPoss() {
    Vector vec = VisualTreeHelper.GetOffset(lab2);
    return new Point(vec.X, vec.Y);
}

看起来运行良好。如果您知道它何时不起作用的场景，请发表评论。

It looks like there is very simple and clear solution:

private Point logicalPoss() {
    Vector vec = VisualTreeHelper.GetOffset(lab2);
    return new Point(vec.X, vec.Y);
}

It looks like it is working well. If you know abou the scenerio when it will not work please leave a comment.

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别靠近我心 2024-10-20 09:24:19

我将获得变换，并将其转换为 MatrixTransform。然后，您可以使用 Inverse 属性来反转渲染变换。它看起来像这样：

private Point visualPoss() 
{
    Point lab2Vis = lab2.PointToScreen(new Point(0, 0));
    Point panVis = pan.PointToScreen(new Point(0, 0));

    if (lab2.RenderTransform != null)
    {
        var matrix = new MatrixTransform(lab2.RenderTransform.Value);
        lab2Vis = matrix.Inverse.Transform(lab2Vis);
    }

    return new Point(lab2Vis.X - panVis.X, lab2Vis.Y - panVis.Y);
}

I would get the transform, and convert it to a MatrixTransform. You can then use the Inverse property to reverse the render transform. It would look something like so:

private Point visualPoss() 
{
    Point lab2Vis = lab2.PointToScreen(new Point(0, 0));
    Point panVis = pan.PointToScreen(new Point(0, 0));

    if (lab2.RenderTransform != null)
    {
        var matrix = new MatrixTransform(lab2.RenderTransform.Value);
        lab2Vis = matrix.Inverse.Transform(lab2Vis);
    }

    return new Point(lab2Vis.X - panVis.X, lab2Vis.Y - panVis.Y);
}

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