设置值正在改变键名

发布于 2024-10-13 08:47:53 字数 374 浏览 2 评论 0原文

var test = {
    one: {},
    two: {},
};
test['two'].parent = test['one'];

我想要测试拥有什么：

test = {
   one: {},
   two: { parent: {}, }

它实际上拥有什么：

 test = {
    parent: {},
    two: { parent: {}, }

为什么 test.one 变成 test.parent？

我希望 test.two.parent 保存对 test.one 的引用。我该怎么做？

原文

var test = {
    one: {},
    two: {},
};
test['two'].parent = test['one'];

what i want test to have:

test = {
   one: {},
   two: { parent: {}, }

what it actually has:

 test = {
    parent: {},
    two: { parent: {}, }

why does test.one become test.parent?

I want test.two.parent to hold a reference to test.one. how would i do this?

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我爱人 2024-10-20 08:47:53

为什么 test.one 变成了 test.parent？

事实并非如此。结果结构为：

{
one: {},
two: { parent: {} }
}

其中 parent 引用的对象与 one 引用的对象相同。

如果你这样做：

test.one.cheese = "crackers";

...下面的结果将是“crackers”

alert(test.two.parent.cheese); // "crackers"

示例： http:// jsfiddle.net/g5chF/

why does test.one become test.parent?

It doesn't. The resulting structure is:

{
one: {},
two: { parent: {} }
}

Where parent is referencing the same object as referenced by one.

If you do:

test.one.cheese = "crackers";

...the result below will be "crackers"

alert(test.two.parent.cheese); // "crackers"

Example: http://jsfiddle.net/g5chF/

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余罪 2024-10-20 08:47:53

您使用什么浏览器？这可能会有所作为。

我在 Firefox 上的 Firebug 中收到了预期的测试结果，但是我不建议混合和匹配属性访问语法（syntaxes？syntaxen？）。

而不是：

test['two'].parent = test['one'];

我会这样做：

test['two']['parent'] = test['one'];

What browser are you using? It may make a difference.

I am receiving expected results testing in Firebug on Firefox, however I wouldn't suggest mixing and matching property access syntax (syntaxes? syntaxen?).

Instead of:

test['two'].parent = test['one'];

I would do:

test['two']['parent'] = test['one'];

回复收藏 0 原文

笑红尘 2024-10-20 08:47:53

您对该声明的作用的主张：

test['two'].parent = test['one'];

不正确。该代码已经完成了您想要的操作：它向 test.two 添加了一个“parent”属性，以便在 test.two.parent 处有一个空对象。

Your claim as to what this statement does:

test['two'].parent = test['one'];

is incorrect. The code already does what you want: it adds a "parent" attribute to test.two, so that there'll be an empty object at test.two.parent.

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