静态错误：此类没有接受 String[] 的 static void main 方法

发布于 2024-10-13 03:04:23 字数 115 浏览 1 评论 0原文

因为我希望用户输入数字而不是我使用的字符串

public static void main(Integer[] args)

所以，为什么这是错误的？

原文

Since I want the user to enter numbers instead of Strings I used

public static void main(Integer[] args)

So, why is this wrong?

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狠疯拽 2024-10-20 03:04:23

您的主要方法上的签名必须是：

public static void main(String[] args)

您没有任何其他选择。如果需要，您可以通过 Integer.parseInt(someString) 将这些字符串解析为整数

The signature on your main method MUST be:

public static void main(String[] args)

You don't have any other option. You may parse those strings as integers if you need to, via Integer.parseInt(someString)

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望笑 2024-10-20 03:04:23

Main 很特殊，因为它必须存在才能启动程序，因此它需要有固定的签名。在底层，java 运行时会寻找魔术签名来启动程序。神奇的签名是

public static void main(String[] args)

如果你想获得整数，你需要事后解析它们，使用

Integer.parseInt( x );

Main is special since it has to be present to start the program, so it's required to have a fixed signature. Under the hood, the java runtime looks for the magic signature to start the program. The magic signature is

public static void main(String[] args)

If you want to get Integers, you'll need to parse them out after the fact, using

Integer.parseInt( x );

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ヤ经典坏疍 2024-10-20 03:04:23

您的 main 方法只能有一个 String[] 数组（除非您重载它，但我们现在不讨论细节 :-D）。

但是，您可以使用 Integer.parseInt，类似

public static void main(String[] args)
{
 int[] values = new int[args.length];
 for (String arg : args)
 {
  //Get or do something with the integer value here
 }
}

这是因为底层平台只知道如何将字符串传递给您的程序。当您打开命令提示符或终端并执行

以下操作时： >java MyClass 3 4 5

它不知道您希望将 ["3","4","5"] 视为整数。它将处理字符串留给程序。

You can only have an array of String[] for your main method (unless you overload it, but let's not get into the details for now :-D).

However, you can change each element of the String[] args into an int by using Integer.parseInt, something like

public static void main(String[] args)
{
 int[] values = new int[args.length];
 for (String arg : args)
 {
  //Get or do something with the integer value here
 }
}

This is because the underlying platform only knows how to pass Strings to your program. When you open up a command prompt or terminal and do:

>java MyClass 3 4 5

It doesn't know that you want ["3","4","5"] treated like integers. It leaves dealing with the Strings up to the program.

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脱离于你 2024-10-20 03:04:23

当 JVM 加载您的类并尝试执行它时，它会查找带有签名的方法 main()

public static void main (String[] args) ...

任何其他内容都是不可接受的。如果您需要整数，请使用 Integer.parseInt() 方法将输入字符串转换为整数，如 Zach 提到的。我将该转换放在 try-catch 块中以捕获 NumberFormatException，并

System.err.println ("This class accepts Integer arguments only");

在相应的 catch 块中添加一个转换。问候， - MS

When the JVM loads your class and tries to execute it, it looks for the method main() with the signature

public static void main (String[] args) ...

Anything else is unaccptable. If you are expecting integers, use the Integer.parseInt() method to convert the input Strings to integers, as Zach mentioned. I'd put that conversion in a try-catch block to catch NumberFormatException, and have a

System.err.println ("This class accepts Integer arguments only");

in the corresponding catch block. Regards, - M.S.

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千柳 2024-10-20 03:04:23

您需要接受一个字符串数组，并在运行时将字符串转换为整数。就按照它的工作方式...

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卷耳 2024-10-20 03:04:23

main 的方法签名始终是 (String[] args)。如果您要获取整数，则必须使用下面的代码片段将 args[] 转换为 int

  int aInt = Integer.parseInt(args[0]);

the method signature for main is always (String[] args). If you are going to get Integers, then you have to convert the args[] to int using the snippet below