从整数组装日期对象？

发布于 2024-10-13 02:50:55 字数 42 浏览 8 评论 0原文

给定三个整数，分别代表日、月和年，什么代码会将这些整数组装成日期对象？

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唱一曲作罢 2024-10-20 02:50:56

您应该查看NSDateComponents：

int y = 2011;
int m = 1;
int d = 15;


NSDateComponents *dc = [[NSDateComponents alloc] init];
[dc setYear:y];
[dc setMonth:m];
[dc setDay:d];

NSLog(@"%@: %@", [[dc date] class], [dc date]);

You should look at NSDateComponents:

int y = 2011;
int m = 1;
int d = 15;


NSDateComponents *dc = [[NSDateComponents alloc] init];
[dc setYear:y];
[dc setMonth:m];
[dc setDay:d];

NSLog(@"%@: %@", [[dc date] class], [dc date]);

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往日 2024-10-20 02:50:56

NSDateFormatter 使用用于将日期字符串解析为日期的 Unicode 标准。因此，将整数格式化为日期字符串，然后使用 NSDateFormatter 来解析它：

// assume year, month and day are integers that are formatted properly and don't
// include invalid ranges
NSString* dateString = [NSString stringWithFormat:@"%04d %02d %02d", year, month, day];
NSDateFormatter* formatter = [[NSDateFormatter alloc] init];
// Choose a format of YEAR MONTH DATE per the standard
[formatter setDateFormat:@"yyyy MM dd"];
NSDate* date = [formatter dateFromString:dateString];
[formatter release];

只要使用 Unicode 标准（上面链接）并将整数转换为相同的格式（显然）。

NSDateFormatter uses the Unicode Standard for parsing date strings into dates. So, format your integers into a date string and then use and NSDateFormatter to parse it:

// assume year, month and day are integers that are formatted properly and don't
// include invalid ranges
NSString* dateString = [NSString stringWithFormat:@"%04d %02d %02d", year, month, day];
NSDateFormatter* formatter = [[NSDateFormatter alloc] init];
// Choose a format of YEAR MONTH DATE per the standard
[formatter setDateFormat:@"yyyy MM dd"];
NSDate* date = [formatter dateFromString:dateString];
[formatter release];

You can set the format string to whatever format floats your boat, as long as you use the Unicode Standard (linked above) and you convert your integers into the same format (obviously).

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