从 S3 存储桶下载 300 万个对象的最快方法

发布于 2024-10-12 15:59:19 字数 475 浏览 8 评论 0原文

我尝试过使用 Python + boto + 多处理、S3cmd 和 J3tset,但都在努力解决。

有什么建议,也许是您一直在使用的现成脚本或我不知道的其他方式?

编辑:

eventlet+boto 是一个有价值的解决方案,如下所述。在这里找到了一篇很好的 eventlet 参考文章 http://web.archive.org/web/20110520140439/http://teddziuba.com/2010/02/eventlet-asynchronous-io-for-g.html

我已经在下面添加了我现在正在使用的 python 脚本。

I've tried using Python + boto + multiprocessing, S3cmd and J3tset but struggling with all of them.

Any suggestions, perhaps a ready-made script you've been using or another way I don't know of?

EDIT:

eventlet+boto is a worthwhile solution as mentioned below. Found a good eventlet reference article here http://web.archive.org/web/20110520140439/http://teddziuba.com/2010/02/eventlet-asynchronous-io-for-g.html

I've added the python script that I'm using right now below.

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(2

木緿 2024-10-19 15:59:19

好的,我根据@Matt Billenstien 的提示找到了一个解决方案。它使用 eventlet 库。这里第一步是最重要的(标准 IO 库的猴子修补)。

使用 nohup 在后台运行此脚本,一切就完成了。

from eventlet import *
patcher.monkey_patch(all=True)

import os, sys, time
from boto.s3.connection import S3Connection
from boto.s3.bucket import Bucket

import logging

logging.basicConfig(filename="s3_download.log", level=logging.INFO)


def download_file(key_name):
    # Its imp to download the key from a new connection
    conn = S3Connection("KEY", "SECRET")
    bucket = Bucket(connection=conn, name="BUCKET")
    key = bucket.get_key(key_name)

    try:
        res = key.get_contents_to_filename(key.name)
    except:
        logging.info(key.name+":"+"FAILED")

if __name__ == "__main__":
    conn = S3Connection("KEY", "SECRET")
    bucket = Bucket(connection=conn, name="BUCKET")

    logging.info("Fetching bucket list")
    bucket_list = bucket.list(prefix="PREFIX")

    logging.info("Creating a pool")
    pool = GreenPool(size=20)

    logging.info("Saving files in bucket...")
    for key in bucket.list():
        pool.spawn_n(download_file, key.key)
    pool.waitall()

Okay, I figured out a solution based on @Matt Billenstien's hint. It uses eventlet library. The first step is most important here (monkey patching of standard IO libraries).

Run this script in the background with nohup and you're all set.

from eventlet import *
patcher.monkey_patch(all=True)

import os, sys, time
from boto.s3.connection import S3Connection
from boto.s3.bucket import Bucket

import logging

logging.basicConfig(filename="s3_download.log", level=logging.INFO)


def download_file(key_name):
    # Its imp to download the key from a new connection
    conn = S3Connection("KEY", "SECRET")
    bucket = Bucket(connection=conn, name="BUCKET")
    key = bucket.get_key(key_name)

    try:
        res = key.get_contents_to_filename(key.name)
    except:
        logging.info(key.name+":"+"FAILED")

if __name__ == "__main__":
    conn = S3Connection("KEY", "SECRET")
    bucket = Bucket(connection=conn, name="BUCKET")

    logging.info("Fetching bucket list")
    bucket_list = bucket.list(prefix="PREFIX")

    logging.info("Creating a pool")
    pool = GreenPool(size=20)

    logging.info("Saving files in bucket...")
    for key in bucket.list():
        pool.spawn_n(download_file, key.key)
    pool.waitall()
往日 2024-10-19 15:59:19

使用 eventlet 为您提供 I/O 并行性,编写一个简单的函数来使用 urllib 下载一个对象,然后使用 GreenPile 将其映射到输入 url 列表 - 一堆 50 到 100 个 greenlet 就可以了...

Use eventlet to give you I/O parallelism, write a simple function to download one object using urllib, then use a GreenPile to map that to a list of input urls -- a pile with 50 to 100 greenlets should do...

~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文