$zip 重命名函数在 PHP 中不起作用

Question

我正在 PHP 中提取一个 zip 文件并尝试将其重命名为 content.txt。这是我的代码：

    if($this->copyFile($this->src,$this->dest)) {
        $this->log .= "Successfully copied the file. Starting unzip.<br />";
        $res = $this->zip->open($this->dest);
        if ($res === TRUE) {
            $this->zip->extractTo("/htdocs/content-refresh/");
            $this->extracted = $this->zip->getNameIndex(0);
            $this->log .= "Extracted ".$this->extracted." onto our server.<br />";
            if($this->zip->renameIndex(0,'content.txt')) {
                $this->log .= "Renamed update file to content.txt.<br />";
            } else {
                $this->log .= "Could not rename update file to content.txt.<br />";
            }
            $this->zip->close();
            $this->log .= "The update file is ready to go. Now you can use the update functions.<br />";
        } else {
            $this->log .= "Could not unzip the file.<br />";
        }
    }

这是文件输出：

Successfully copied the file. Starting unzip.

Extracted Hotel_All_Active 01-19-11.txt onto our server.

Renamed update file to content.txt.

The update file is ready to go. Now you can use the update functions.

问题是它没有重命名文件。我也尝试过：

$this->zip->renameName(strval($this->extracted),'content.txt')

但这也打印出它重命名了文件，但没有。我在这里做错了什么，还是这个函数有问题？

Answer 1

renameIndex() 函数是用于重命名存档内的文件。

查看 PHP 手册中该函数的代码，您可以看到它正在修改存档：

$zip = new ZipArchive;
$res = $zip->open('test.zip');
if ($res === TRUE) {
    $zip->renameIndex(2,'newname.txt');
    $zip->close();
} else {
    echo 'failed, code:' . $res;
}

您需要使用 rename() 函数代替。