Java运行时错误”无限小数扩展；没有精确可表示的十进制结果”在 BigDecimal 类中

Question

当我选择“正不当积分”或“负不当积分”时，它给我一个错误 错误是线程“main”java.lang.ArithmeticException中的异常：非终止十进制扩展；没有精确可表示的十进制结果。

 at java.math.BigDecimal.divide(BigDecimal.java:1603)
 at SE_Project_2.calculate(SE_Project_2.java:55)
 at SE_Project_2.main(SE_Project_2.java:45)

代码：

 import java.math.BigDecimal;
 import javax.swing.JOptionPane;

 public class SE_Project_2 {

  private static BigDecimal C0 =   new BigDecimal("0.1713245");
  private static BigDecimal C1 =   new BigDecimal("0.3607616");
  private static BigDecimal C2 =   new BigDecimal("0.4679139");
  private static BigDecimal C3 =   new BigDecimal("0.4679139");
  private static BigDecimal C4 =   new BigDecimal("0.3607616");
  private static BigDecimal C5 =   new BigDecimal("0.1713245");
  private static BigDecimal X0 =   new BigDecimal("-0.932469514");
  private static BigDecimal X1 =   new BigDecimal("-0.661209386");
  private static BigDecimal X2 =   new BigDecimal("-0.238619186");
  private static BigDecimal X3 =   new BigDecimal("0.238619186");
  private static BigDecimal X4 =   new BigDecimal("0.661209386");
  private static BigDecimal X5 =   new BigDecimal("0.932469514");
  private static BigDecimal a=new BigDecimal("0"),b=new BigDecimal("0");
  private static int y;
     public static void main(String[] args) {
         Scanner in = new Scanner(System.in);
         try{
          String[] o = {"Positive improper integration","Negative improper integration","Normal integration"};
          y = JOptionPane.showOptionDialog(null,"Welcome to my program! \nYahya Al-Buluwi\nIt can work for big decimal numbers.\n\nThis program will find the integral of: \nf(x)= 5x + 3 dx\nBy using the 6-points Gauss Legendre Quadrature formulae.\n\n What choise is prefered to you?","Welcome",JOptionPane.YES_NO_CANCEL_OPTION,JOptionPane.QUESTION_MESSAGE,null,o,o[2]);
    BigDecimal sum = null;


if (y==2){
 a = new BigDecimal((String)JOptionPane.showInputDialog(null,"Enter the value of a:","Enter the value of a", JOptionPane.QUESTION_MESSAGE));
       b = new BigDecimal((String)JOptionPane.showInputDialog(null,"Enter the value of b:","Enter the value of b", JOptionPane.QUESTION_MESSAGE));
}
sum = calculate(X0,C0).add(calculate(X1,C1).add(calculate(X2,C2)).add(calculate(X3,C3).add(calculate(X4,C4).add(calculate(X5,C5)))));
System.out.println("y=" + y);
JOptionPane.showMessageDialog(null,"The 6-points Gauss Legendre Quadrature formulae solution according to \na= " + a+"\nb= "+b+" \nis:   "+ sum,"Result",JOptionPane.INFORMATION_MESSAGE);

     }catch(Exception e){
      JOptionPane.showMessageDialog(null,"Ooops! an error has occured! the program will be terminated.","Error",JOptionPane.ERROR_MESSAGE);
      calculate(X0,C0).add(calculate(X1,C1).add(calculate(X2,C2)).add(calculate(X3,C3).add(calculate(X4,C4).add(calculate(X5,C5)))));
System.out.println("y=" + y);
JOptionPane.showMessageDialog(null,"The 6-points Gauss Legendre Quadrature formulae solution according to \na= " + a+"\nb= "+b+" \nis:   "+  calculate(X0,C0).add(calculate(X1,C1).add(calculate(X2,C2)).add(calculate(X3,C3).add(calculate(X4,C4).add(calculate(X5,C5))))),"Result",JOptionPane.INFORMATION_MESSAGE);

     }
 }
public static BigDecimal calculate(BigDecimal x, BigDecimal c){
  BigDecimal h = x.multiply(new BigDecimal("0.5"));
  if(y==0){
   //     PI= (1/(.5x)**2)*((5/(.5+.5x))+3)
   return (((new BigDecimal("1")).divide(h.pow(2))).multiply((new BigDecimal("3")).add((new BigDecimal("5")).divide((new BigDecimal("0.5")).add(h)))));
  }
  if(y==1){
   //        NI= (1/(-.5x)**2)*((5/(-.5-.5x))+3)
   return ((new BigDecimal("1").divide((h.negate()).pow(2))).multiply(new BigDecimal("3").add(new BigDecimal("5").divide(new BigDecimal("-0.5").add(h.negate())))));
  }

 BigDecimal sum = (b.add(a)).divide(new BigDecimal("2"));
    BigDecimal diff =(b.add(a.negate())).divide(new BigDecimal("2"));
    return c.multiply(diff.multiply((((diff.multiply(x)).add(sum)).multiply(new BigDecimal("5"))).add(new BigDecimal("3"))));

}
}

Answer 1

您可能需要使用 divide 指定舍入模式的方法。

另请阅读此处。

Answer 2

当您对 BigDecimal 执行 1/3 并且没有指定结果的精确度以及舍入方法应该是什么样时，就会发生这种情况。
请参阅 javadoc (http://download.oracle.com/ javase/6/docs/api/java/math/BigDecimal.html)
您可以使用 MathContext 对象将 precision 和 roundupMethod 包装在一起。您也可以选择直接指定。将这些信息添加到构造函数中或在调用 div 时都可以。

Answer 3

如果结果数字具有无限小数扩展，则 Divide 方法将引发此异常。在这种情况下，您需要提供一个 MathContext，它将定义如何对数字进行舍入，以便它具有有限值。