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C++：计算移动 FPS

发布于 2024-10-12 03:00:18 字数 79 浏览 3 评论 0原文

我想计算游戏最后2-4秒的FPS。最好的方法是什么？

谢谢。

编辑：更具体地说，我只能访问以一秒为增量的计时器。

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誰ツ都不明白 2024-10-19 03:00:18

差点错过了最近的一个帖子。请参阅我对使用指数加权移动平均线的回复。

C++：计算游戏中的总帧数

这是示例代码。

最初：

avgFps = 1.0; // Initial value should be an estimate, but doesn't matter much.

每秒（假设最后一秒的总帧数在framesThisSecond中）：

// Choose alpha depending on how fast or slow you want old averages to decay.
// 0.9 is usually a good choice.
avgFps = alpha * avgFps + (1.0 - alpha) * framesThisSecond;

Near miss of a very recent posting. See my response there on using exponential weighted moving averages.

C++: Counting total frames in a game

Here's sample code.

Initially:

avgFps = 1.0; // Initial value should be an estimate, but doesn't matter much.

Every second (assuming the total number of frames in the last second is in framesThisSecond):

// Choose alpha depending on how fast or slow you want old averages to decay.
// 0.9 is usually a good choice.
avgFps = alpha * avgFps + (1.0 - alpha) * framesThisSecond;

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难以启齿的温柔 2024-10-19 03:00:18

这是一个可能适合您的解决方案。我将用伪/C 语言编写此内容，但您可以根据您的游戏引擎调整该想法。

const int trackedTime = 3000; // 3 seconds
int frameStartTime; // in milliseconds
int queueAggregate = 0;
queue<int> frameLengths;

void onFrameStart()
{
    frameStartTime = getCurrentTime();
}

void onFrameEnd()
{
    int frameLength = getCurrentTime() - frameStartTime;

    frameLengths.enqueue(frameLength);
    queueAggregate += frameLength;

    while (queueAggregate > trackedTime)
    {
        int oldFrame = frameLengths.dequeue();
        queueAggregate -= oldFrame;
    }

    setAverageFps(frameLength.count() / 3); // 3 seconds
}

Here's a solution that might work for you. I'll write this in pseudo/C, but you can adapt the idea to your game engine.

const int trackedTime = 3000; // 3 seconds
int frameStartTime; // in milliseconds
int queueAggregate = 0;
queue<int> frameLengths;

void onFrameStart()
{
    frameStartTime = getCurrentTime();
}

void onFrameEnd()
{
    int frameLength = getCurrentTime() - frameStartTime;

    frameLengths.enqueue(frameLength);
    queueAggregate += frameLength;

    while (queueAggregate > trackedTime)
    {
        int oldFrame = frameLengths.dequeue();
        queueAggregate -= oldFrame;
    }

    setAverageFps(frameLength.count() / 3); // 3 seconds
}

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半暖夏伤 2024-10-19 03:00:18

可以保留最后 100 帧的帧时间的循环缓冲区，并对它们进行平均吗？这将是“最后 100 帧的 FPS”。（或者更确切地说，99，因为您无法区分最新时间和最旧时间。）

调用一些准确的系统时间，毫秒或更好。

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木有鱼丸 2024-10-19 03:00:18

你真正想要的是这样的（在你的 mainLoop 中）：

frames++;
if(time<secondsTimer()){
  time = secondsTimer();
  printf("Average FPS from the last 2 seconds: %d",(frames+lastFrames)/2);
  lastFrames = frames;
  frames = 0;
}

如果你知道如何处理结构/数组，那么你应该很容易将此示例扩展到 4 秒而不是 2 秒。但是如果你想要更详细的帮助，你真的应该提到为什么你无法访问精确的计时器（哪种架构，语言） - 否则一切就像猜测......

What you actually want is something like this (in your mainLoop):

frames++;
if(time<secondsTimer()){
  time = secondsTimer();
  printf("Average FPS from the last 2 seconds: %d",(frames+lastFrames)/2);
  lastFrames = frames;
  frames = 0;
}

If you know, how to deal with structures/arrays it should be easy for you to extend this example to i.e. 4 seconds instead of 2. But if you want more detailed help, you should really mention WHY you haven't access to an precise timer (which architecture, language) - otherwise everything is like guessing...

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