Flash：调整此代码以保留重复的影片剪辑

发布于 2024-10-12 02:25:55 字数 465 浏览 2 评论 0原文

好的，这是我的代码

ham_mc.onPress=function(){
startDrag(this);
}
ham_mc.onRelease=ham_mc.onReleaseOutside=function(){
stopDrag();
_root.ham_mc.duplicateMovieClip("ham_mc" + "x",2);
x++;
}

用户可以首先拖动影片剪辑。释放后，duplicateMovieClip 命令将运行，在第一个拖动到的位置留下一个新的 ham 影片剪辑。

问题：当我再次单击并拖动第一个火腿影片时，duplicateMovieClip 会再次运行，但会替换以前生成的影片剪辑。

我添加了 x 和 x++ 试图每次为影片剪辑重复项指定不同的名称，但这并不能解决问题。

我如何更改此代码，以便每次都创建一个新的 ham_mc，而不是覆盖旧的。我累了，抱歉解释不好！

原文

OK, so here is my code

ham_mc.onPress=function(){
startDrag(this);
}
ham_mc.onRelease=ham_mc.onReleaseOutside=function(){
stopDrag();
_root.ham_mc.duplicateMovieClip("ham_mc" + "x",2);
x++;
}

The user can at first drag the movie clip. When released, the duplicateMovieClip command runs, leaving a new ham movie clip in the position the first is dragged to.

PROBLEM: When I click and drag the first ham movie click again, the duplicateMovieClip runs again but REPLACES the previous generated movie clip.

I added x and x++ in an attempt to give the movie clip duplication a different name every time, but this doesn't solve it.

How do I change this code so that a NEW ham_mc is created every time, rather than overwriting the old one. I'm tired, sorry for the poor explaination!

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仅此而已 2024-10-19 02:25:55

这不是名称 - 而是您在 (2) 处加载它的深度。尝试用 x 替换 2，它应该适合您：

ham_mc.onPress=function(){
startDrag(this);
}
ham_mc.onRelease=ham_mc.onReleaseOutside=function(){
stopDrag();
_root.ham_mc.duplicateMovieClip("ham_mc" + x ,x);
_root['ham_mc' + x]._x = 50;
_root['ham_mc' + x]._y = 50;
x++;
}

在相同深度加载剪辑将始终替换之前在该深度加载的剪辑。

编辑并测试:)

It's not the name - it's the depth that you're loading it at (2). Try replacing 2 with x and it should work for you:

ham_mc.onPress=function(){
startDrag(this);
}
ham_mc.onRelease=ham_mc.onReleaseOutside=function(){
stopDrag();
_root.ham_mc.duplicateMovieClip("ham_mc" + x ,x);
_root['ham_mc' + x]._x = 50;
_root['ham_mc' + x]._y = 50;
x++;
}

Loading clips at the same depth will always replace the clip previously loaded at that depth.

Edited and tested :)

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时常饿 2024-10-19 02:25:55

Demian 的答案是正确的，但前提是您的 x 计数与舞台上的 MovieClip 总数相匹配。此外，所有剪辑都设置为相同的 X 和 Y 位置。这应该效果更好：

ham_mc.onPress=function(){
    startDrag(this);
}
ham_mc.onRelease=ham_mc.onReleaseOutside=function(){
    stopDrag();
    _root.ham_mc.duplicateMovieClip("ham_mc" + x ,_root.getNextHighestDepth());
    _root['ham_mc' + x]._x = _root._xmouse;
    _root['ham_mc' + x]._y = _root._ymouse;
    x++;
}

Demian's answer is correct, but only if your x count matches the total number of MovieClips on the stage. Also, all clips are set to the same X and Y position. This should work better:

ham_mc.onPress=function(){
    startDrag(this);
}
ham_mc.onRelease=ham_mc.onReleaseOutside=function(){
    stopDrag();
    _root.ham_mc.duplicateMovieClip("ham_mc" + x ,_root.getNextHighestDepth());
    _root['ham_mc' + x]._x = _root._xmouse;
    _root['ham_mc' + x]._y = _root._ymouse;
    x++;
}

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~没有更多了~