XSLT 错误“不是节点项”
我正在尝试从平面结构创建嵌套层次结构，并且使用以下键：
<xsl:key name="next-headings"
match="w:p[w:pPr/w:pStyle/@w:val = 'Heading3']"
use="generate-id((ancestor::w:sdt[1] |
preceding-sibling::w:p
[w:pPr/w:pStyle/@w:val = 'Heading1'] or
preceding-sibling::w:p
[w:pPr/w:pStyle/@w:val = 'Heading2']
)[last()])"/>
我收到“不是节点项”错误，但不明白为什么。非常感谢任何翻译此错误的帮助！
I'm trying to create a nested hierarchy from a flat structure, and I am using the following key:
<xsl:key name="next-headings"
match="w:p[w:pPr/w:pStyle/@w:val = 'Heading3']"
use="generate-id((ancestor::w:sdt[1] |
preceding-sibling::w:p
[w:pPr/w:pStyle/@w:val = 'Heading1'] or
preceding-sibling::w:p
[w:pPr/w:pStyle/@w:val = 'Heading2']
)[last()])"/>
I am getting the "not a node item" error, but don't understand why. Any help in translating this error is much appreciated!
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评论（2）
正如 @LarsH 所回答的，
or运算符比|联合运算符具有更高的优先级，并且它会产生一个无法联合到节点集的布尔表达式。但是，除此之外，您似乎想将
or运算符替换为|联合，我会使用以下表达式：编辑：小拼写错误...
As @LarsH has answered, the
oroperator has more precedence that|union operator, and it results in a boolean expression that you can't union to a node set.But, besides that it looks like you want to replace the
oroperator for a|union, I would use this expression:Edit: little typo...
我认为您需要将
or更改为|。您的意思是通过联合 (|) 创建节点集，但or运算符返回一个布尔值，它“不是节点项”。I think you need to change
orto|. You meant create a nodeset via union (|), but theoroperator returns a boolean value, which is "not a node item".