仅当键没有值时如何删除哈希键？
我构建了一个循环，查找特定虚拟机的所有 VMDK，然后创建输出的哈希值，然后通过在 VMX 文件中查找参数来测试磁盘是否实际存在。然后，如果磁盘不存在，则会将其从哈希中删除。我遇到的问题是如何删除没有定义磁盘的哈希键。
这是代码块；
while ($vmx_file =~ m/^(ide(?<PORT>[0-1])\:(?<DISK>[0-1]))\.present\s+=\s+"(?<PRESENT>[^"]+)["]/xmg) {
$ide_port = "$+{PORT}";
$ide_disk = "$+{DISK}";
$present = "$+{PRESENT}";
if ($present eq 'FALSE') {
delete $virtual_disks{$vm}{"IDE$ide_port"}{"Disk$ide_disk"}
}
}
当上述语句成立并且删除丢失的磁盘时，这就是我得到的哈希值。
$VAR1 = {
'Test01' => {
'SCSI0' => {
'Disk0' => '/vmfs/volumes/4c8fd27b-5876fc36-80f4-0015179fd63c/Test01/Test01.vmdk',
'Type' => 'lsilogic',
'Disk1' => '/vmfs/volumes/4c8fd27b-5876fc36-80f4-0015179fd63c/Test01/Test01_1.vmdk'
},
'IDE1' => {
'Disk0' => '/vmfs/volumes/4c8fd27b-5876fc36-80f4-0015179fd63c/ubuntu-10.10-desktop-i386.iso'
},
'IDE0' => {}
}
正如您所看到的，子哈希“IDE0”为空，因为列出的磁盘不存在于 VMX 文件中。现在我想做的是删除整个“IDE0”哈希，因为其中没有任何内容。但是我只希望它在没有哈希值的情况下删除它，因为根据 IDE 规范，它最多可以有 2 个磁盘。
I have built a loop that finds all of the VMDKs for a perticular VM and then create a hash of the output, then it tests whether the disk is actually present by looking for a parameter in the VMX file. Then if the disk is not present it deletes it from the hash. The problem I running into is how to delete a hash key that has no disks defined.
Here is the code block;
while ($vmx_file =~ m/^(ide(?<PORT>[0-1])\:(?<DISK>[0-1]))\.present\s+=\s+"(?<PRESENT>[^"]+)["]/xmg) {
$ide_port = "$+{PORT}";
$ide_disk = "$+{DISK}";
$present = "$+{PRESENT}";
if ($present eq 'FALSE') {
delete $virtual_disks{$vm}{"IDE$ide_port"}{"Disk$ide_disk"}
}
}
This is what I am getting as a hash when the above statement is true and it deletes the missing disks.
$VAR1 = {
'Test01' => {
'SCSI0' => {
'Disk0' => '/vmfs/volumes/4c8fd27b-5876fc36-80f4-0015179fd63c/Test01/Test01.vmdk',
'Type' => 'lsilogic',
'Disk1' => '/vmfs/volumes/4c8fd27b-5876fc36-80f4-0015179fd63c/Test01/Test01_1.vmdk'
},
'IDE1' => {
'Disk0' => '/vmfs/volumes/4c8fd27b-5876fc36-80f4-0015179fd63c/ubuntu-10.10-desktop-i386.iso'
},
'IDE0' => {}
}
As you can see the sub hash 'IDE0" is empty, because the disk that was listed was not present in the VMX file. Now what I would like to do is remove the entire 'IDE0' hash because there is nothing in it. But I only want it to delete it if it hash nothing. becasue it can have up to 2 disks in it as per IDE specs. Follow me?
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计算第一轮删除后剩余的密钥。如果计数为零，则在更高级别删除。
Count the remaining keys after your first round of deletion. If the count is zero, delete at the higher level.