关于 GregorianCalendar：java 中相同的输入但不同的输出
我想在程序中使用毫秒设置新日期，但它不起作用。有人可以告诉我为什么它不起作用吗？
日历 r_1 = new GregorianCalendar(2011,0,1);
r_1.add(日历.DAY_OF_MONTH,2);
System.out.println(r_1.getTime());
长date_1 = r_1.getTimeInMillis() + 2*24*60*60*1000;
r_1.setTimeInMillis(startTime1);
System.out.println(r_1.getTime());
它工作得非常正确，但如果我将日期从 2 更改为 25，那么它就工作了。
----------输出正确，是2011/01/26 ----------
Calendar r_1 = new GregorianCalendar(2011,0,1);
r_1.add(日历.DAY_OF_MONTH,25);
System.out.println(r_1.getTime());
-----------现在输出不正确，是2010/12/07-----
long date_1 = r_1.getTimeInMillis() + 25*24*60*60*1000;/ /i 将 2 更改为 25
r_1.setTimeInMillis(startTime1);
System.out.println(r_1.getTime());
谢谢
I want to use milliseconds to set a new date in my program,but it doesnt work. Is there anybody can tell me why it doesnt work?
Calendar r_1 = new GregorianCalendar(2011,0,1);
r_1.add(Calendar.DAY_OF_MONTH,2);
System.out.println(r_1.getTime());
long date_1 = r_1.getTimeInMillis() + 2*24*60*60*1000;
r_1.setTimeInMillis(startTime1);
System.out.println(r_1.getTime());
It works both very correct , but if i change the day from 2 to 25,then it doenst work .
----------the output is correct ,it is 2011/01/26 ----------
Calendar r_1 = new GregorianCalendar(2011,0,1);
r_1.add(Calendar.DAY_OF_MONTH,25);
System.out.println(r_1.getTime());
-----------the output is incorrect now ,it is 2010/12/07------
long date_1 = r_1.getTimeInMillis() + 25*24*60*60*1000;//i have change 2 to 25
r_1.setTimeInMillis(startTime1);
System.out.println(r_1.getTime());
Thanks
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表达式
25*24*60*60*1000是一个整数，并且您已经溢出了整数的大小，从而创建了一个负数。你的表达式是2,160,000,000毫秒。 int 可以容纳的最大值是 2,147,483,647。
要解决此问题，您必须强制表达式为 long，如下所示
The expression
25*24*60*60*1000is an integer, and you have overflowed the size of an integer, creating a negative number.Your expression is 2,160,000,000 milliseconds. The largest value an int can hold is 2,147,483,647.
To fix this, you have to force the expression to be a long, as follows
25*24*60*60*1000太大，无法放入int中。尝试
25L*24*60*60*1000这是一个长常量。25*24*60*60*1000is too large to fit in anint.Try
25L*24*60*60*1000which is a long constant.尝试这样的事情：
Try something like that: