获得我的域名 (facebook) 上的所有点赞
我正在尝试获取我的域上的点赞统计信息。我想获得我的域（有数万个页面）上所有页面的所有赞（如果可能的话，使用用户 ID）
domain_like_adds 实际返回什么？
从见解中选择指标、价值 WHERE object_id=[域 ID] AND metric='domain_like_adds' 并且 end_time=end_time_date('2011-01-03') AND period=period('月')
返回空白，有谁知道domain_like_adds返回什么数据？
问候， 尼克拉斯
I'm trying to get statistics for likes on my domain. I would like to get all likes (if possible with user ids) for all pages on my domain (which has tens of thousands of pages)
What does domain_like_adds actually return?
SELECT metric, value FROM insights
WHERE object_id=[domain-id] AND
metric='domain_like_adds' AND
end_time=end_time_date('2011-01-03')
AND period=period('month')
Returns blank, does anyone know what data domain_like_adds returns?
Regards,
Niklas
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我不认为您可以通过任何方式获取用户 ID，因为这是对隐私的重大侵犯，但我相信
domain_like_adds表明您的域名在给定时间段内获得了多少个新点赞，如下所示与您的域名在此之前获得的累积点赞相反。似乎没有一种可行的方法可以始终确定域中所有对象的点赞数，而无需从头开始跟踪和/或返回并总结历史数据。I don't think there's any way you're going to get user IDs as that is a major privacy invasion, but I believe
domain_like_addsindicates how many NEW likes your domain got in the given time period, as opposed to the cumulative likes your domain has earned until that point. It doesn't appear there's a viable way to determine the # of likes of all objects in your domain for all time without tracking it from the beginning and/or going back and summing up historical data.您可以为您的网站制作 sitemap.xml 并根据 Facebook Graph API 抓取 URL。我实际上制作了一个 Ruby 脚本来执行此操作： http:// bobbelderbos.com/2012/01/ruby-script-facebook-like-stats-blog/。我认为您无法让用户“喜欢”您的页面，但此脚本可能有助于找出哪些 URL 最受欢迎。
You can make a sitemap.xml of your site and crawl the urls against the Facebook Graph API. I actually made a Ruby script to do this: http://bobbelderbos.com/2012/01/ruby-script-facebook-like-stats-blog/. I don't think you can get the users that 'liked' your pages, but this script might be useful to find out what URLs are most popular.