等效 C++ python 中的嵌套打印

Question

我正在尝试在 python 中运行此 C++ 语句，但在将打印放入循环中时遇到问题。

for (int i = 0; i < 3; i++)
{
    for (int j = 0; j < 3; j++)
    {
        for (int k = 0; k < 3; k++)
        {
          cout<<_3x3x3[i][j][k]<<" ";
        }
    }
     //print here in python
     cout<<endl;
}

在Python中：

_3x3x3 = [[[0 for col in range(3)] for row in range(3)] for depth in range(3)]

for i in range(3):
    for j in range(3):
        for k in range(3):
            _3x3x3[i][j][k] = 1

for col in _3x3x3:
    print col
print
for row in _3x3x3:
    print row
print
for depth in _3x3x3:
    print depth
#I want to print this in the C++ style above
for i in range(3):
    for j in range(3):
        for k in range(3):
            print _3x3x3[i][j][k]

Answer 1

for i in range(3):
    for j in range(3):
        for k in range(3):
            # something here
            print _3x3x3[i][j][k],
    print

Answer 2

为了多样性和面向未来：

from __future__ import print_function

for i in range(3):
    print(*(_3x3x3[i][j][k] for j in range(3) for k in range(3)))

此代码与 C++ 代码之间的区别在于，它不会在每行末尾、换行符之前输出空格。不过，这可能是一件好事。