Windows 任务计划程序：IAction.QueryInterface() 返回错误我找不到其定义

发布于 2024-10-11 10:18:24 字数 722 浏览 3 评论 0原文

我正在尝试使用 C++ win32 安排任务（在特定时间打开 .exe）。但在一个特定的点上，我收到了一个错误，我已经搜索了 &搜索并尝试找到这个错误的定义但我找不到它？

你知道这个错误是什么意思吗：十六进制：80004003 十进制：2147500035

我不会发布整个函数，因为它相当长（除非您可能需要它来确定错误上下文？）。 em>

我正在使用的代码（导致错误）如下：

//  QI for the executable task pointer.
hr = action -> QueryInterface( IID_IExecAction, (void**) execAction );
action -> Release();

if( FAILED(hr) )
{
    printf("QueryInterface call failed for IExecAction: %x %X %u \n", hr, hr, hr );
    rootFolder -> Release();
    task -> Release();
    CoUninitialize();
    return false;
}

输出为：IExecAction 的 QueryInterface 调用失败：80004003 80004003 2147500035

原文

I am attempting to schedule a task (to open an .exe at a specific time) using C++ win32. But at one specific point I am getting an error, I have searched & searched to try & find the definition of this error but I cannot find it?

Do you know what this error means: Hexadecimal: 80004003 Decimal: 2147500035

I wont post the whole function because its rather long (unless you may need it to determine the error context?).

The code I am using (that causes the error) is the following:

//  QI for the executable task pointer.
hr = action -> QueryInterface( IID_IExecAction, (void**) execAction );
action -> Release();

if( FAILED(hr) )
{
    printf("QueryInterface call failed for IExecAction: %x %X %u \n", hr, hr, hr );
    rootFolder -> Release();
    task -> Release();
    CoUninitialize();
    return false;
}

The output is: QueryInterface call failed for IExecAction: 80004003 80004003 2147500035

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

御守 2024-10-18 10:18:24

0x80004003 是“无效指针”错误，又名 E_POINTER。

我假设 execAction 的声明类似于：

IExecAction* execAction = NULL;

但是，QueryInterface 需要一个指向接口指针的指针。换句话说，您传递一个存储位置来放置 IUnknown*...，或者在本例中为 IExecAction*。

因此，您需要传递 execAction 的地址，以便 QueryInterface 可以将接口指针返回给您。如：

hr = action -> QueryInterface( IID_IExecAction, (void**) &execAction );

我认为这就是发生的情况，因为将指针值初始化为 NULL 是一种常见的编码实践，并且 QueryInterface 已记录，以在第二个参数为 NULL 时返回 E_POINTER。如果没有，请使用 execAction 声明更新您的问题。

0x80004003 is an "invalid pointer" error, a.k.a. E_POINTER.

I assume the declaration of execAction is something like:

IExecAction* execAction = NULL;

But, QueryInterface expects a pointer to an interface pointer. In other words, you pass a storage location in which to place an IUnknown*... or, in this specific case, a IExecAction*.

So, you need to pass the address of execAction so QueryInterface can return the interface pointer to you. As in:

hr = action -> QueryInterface( IID_IExecAction, (void**) &execAction );

I assume this is what's happening since initializing pointer values to NULL is a common coding practice, and QueryInterface is documented to return E_POINTER when the second argument is NULL. If not, please update your question with the declaration of execAction.

回复收藏 0 原文

~没有更多了~