copyWithZone 返回值所有权并保留计数
我在苹果文档中读到有关 copyWithZone 的内容：
“返回的对象隐式由发送者保留，发送者负责释放它”。
因此，如果我写这个 :
- (id)copyWithZone:(NSZone *)zone {
MyObject* obj = [[[[self class] allocWithZone:zone] init] autorelease];
[obj fillTheObj];
return obj;
}
并调用 : ，
MyStuff* obj = [varobj copy];
obj 会被保留吗？如果我不设置自动释放，那么保留计数会怎样？
I read in the apple documentation about copyWithZone :
"The returned object is implicitly retained by the sender, who is responsible for releasing it".
So if I write this :
- (id)copyWithZone:(NSZone *)zone {
MyObject* obj = [[[[self class] allocWithZone:zone] init] autorelease];
[obj fillTheObj];
return obj;
}
and I call :
MyStuff* obj = [varobj copy];
will obj be retained? What about the retain count if I don't set autorelease?
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评论（1）
不要在您的
copyWithZone方法中自动释放它，否则您将不会拥有它（并且可能甚至无法用它做任何事情）。删除自动释放，
obj将适当保留在MyStuff复制中。您只需在完成后release它即可。Apple 的句子是说发送者（即您的
MyStuff *obj初始化）拥有所有权并需要释放它。 “发送者”指的是发送copy消息的对象，而不是您的copyWithZone方法。Do not autorelease it in your
copyWithZonemethod or you won't own it (and likely won't be able to even do anything with it).Remove the autorelease and
objwill be appropriately retained in theMyStuffcopying. You simply need toreleaseit when you're done with it.The Apple sentence is saying that the sender -- which is your
MyStuff *objinitialization -- has ownership and needs to release it. "Sender" refers to the object that sent thecopymessage, not yourcopyWithZonemethod.