Ruby Timeout::timeout 不会引发异常，也不会返回记录的内容

发布于 2024-10-11 01:57:56 字数 517 浏览 6 评论 0原文

我有这段代码：

begin
  complete_results = Timeout.timeout(4) do      
    results = platform.search(artist, album_name)
  end
rescue Timeout::Error
  puts 'Print me something please'
end

然后启动包含此代码的方法，好吧，这是堆栈跟踪的开始：

Exception message :  execution expired
Exception backtrace :  /***/****/.rvm/rubies/ruby-1.8.7-p302/lib/ruby/1.8/timeout.rb:64:i

所以我天真地认为我的调用超时了，但是“请打印一些东西”永远不会被打印并且< code>complete_results 假设是超时状态返回值（true 或 false，如文档中所述），绝对不是布尔值。

我做错了什么吗？

原文

I have this piece of code:

begin
  complete_results = Timeout.timeout(4) do      
    results = platform.search(artist, album_name)
  end
rescue Timeout::Error
  puts 'Print me something please'
end

I then launch the method containing this code, and well, here is the beginning of a stack trace:

Exception message :  execution expired
Exception backtrace :  /***/****/.rvm/rubies/ruby-1.8.7-p302/lib/ruby/1.8/timeout.rb:64:i

So I naively thinks that my call timed out, but 'Print me something please' is never printed and complete_results which is suppose to be the timeout status return value (either true or false, as mentioned in the documentation), is definitively not a boolean.

Am I doing something wrong?

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

静水深流 2024-10-18 01:57:56

您的代码是正确的

require 'timeout'
begin
  complete_results = Timeout.timeout(1) do      
   sleep(2)
  end
rescue Timeout::Error
  puts 'Print me something please'
end

，确实打印出“请给我打印一些东西”。

尝试上面的基本代码。如果有效，则说明 platform.search 中存在问题。

Your code is correct

require 'timeout'
begin
  complete_results = Timeout.timeout(1) do      
   sleep(2)
  end
rescue Timeout::Error
  puts 'Print me something please'
end

does print out "print me something please".

Try the basic code as above. If that works, you have an issue in platform.search.

回复收藏 0 原文

深居我梦 2024-10-18 01:57:56

问题是 platform.search 正在捕获 Timeout#timeout 抛出的异常。

您可以通过将内部代码包装在另一个线程中来解决这个问题 - YMMV。

begin
  complete_results = Timeout.timeout(4) do
    Thread.new{ results = platform.search(artist, album_name) }.value
  end
rescue Timeout::Error
  puts 'Print me something please'
end

The problem is that platform.search is catching the exception that Timeout#timeout throws.

You can get around this by wrapping your inner code in another thread -- YMMV.

begin
  complete_results = Timeout.timeout(4) do
    Thread.new{ results = platform.search(artist, album_name) }.value
  end
rescue Timeout::Error
  puts 'Print me something please'
end

回复收藏 0 原文