无法解析为整数

发布于 2024-10-10 19:58:13 字数 1310 浏览 8 评论 0原文

好吧...我有这个 .txt 文件 (UTF-8)

4661,SOMETHING,3858884120607,24,24.09
4659,SOMETHING1,3858884120621,24,15.95
4660,SOMETHING2,3858884120614,24,19.58

和这段代码

FileInputStream fis = new FileInputStream(new File(someTextFile.txt));
InputStreamReader isr = new InputStreamReader(fis, "UTF-8");
BufferedReader in = new BufferedReader(isr);

int i = 0;
String line;
while((line = in.readLine()) != null) {
Pattern p = Pattern.compile(",");
String[] article = p.split(line);

// I don't know why but when a first line starts with
// an integer - article[0] (which in .txt file is 4661)
// becomes someWeirdCharacter4661 so I need to trim it
// *weird character is like |=>|

if (i == 0) {
    StringBuffer articleCode = new StringBuffer(article[0]);
    articleCode.deleteCharAt(0);
    article[0] = articleCode.toString();
}

SomeArticle**.addOrChange(mContext, Integer.parseInt(article[0]), article[1], article[2], Integer.parseInt(article[3]), Double.parseDouble(article[4]));

i++;
}

在模拟器上没问题，但在真实设备 (HTC Desire) 上我收到这个（奇怪的）错误：

E/AndroidRuntime(16422): java.lang.NumberFormatException: unable to parse '4661' as integer

What's the the问题？

** 这只是我的一些类需要这些参数作为输入（上下文，int，字符串，字符串，int，double）

原文

Alright...I have this .txt file (UTF-8)

4661,SOMETHING,3858884120607,24,24.09
4659,SOMETHING1,3858884120621,24,15.95
4660,SOMETHING2,3858884120614,24,19.58

And this code

FileInputStream fis = new FileInputStream(new File(someTextFile.txt));
InputStreamReader isr = new InputStreamReader(fis, "UTF-8");
BufferedReader in = new BufferedReader(isr);

int i = 0;
String line;
while((line = in.readLine()) != null) {
Pattern p = Pattern.compile(",");
String[] article = p.split(line);

// I don't know why but when a first line starts with
// an integer - article[0] (which in .txt file is 4661)
// becomes someWeirdCharacter4661 so I need to trim it
// *weird character is like |=>|

if (i == 0) {
    StringBuffer articleCode = new StringBuffer(article[0]);
    articleCode.deleteCharAt(0);
    article[0] = articleCode.toString();
}

SomeArticle**.addOrChange(mContext, Integer.parseInt(article[0]), article[1], article[2], Integer.parseInt(article[3]), Double.parseDouble(article[4]));

i++;
}

On emulator it's fine but on real device (HTC Desire) I get this (weird) error:

E/AndroidRuntime(16422): java.lang.NumberFormatException: unable to parse '4661' as integer

What's the problem?

** it's just some my class which needs those parameters as input (context,int,string,string,int,double)

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征棹 2024-10-17 19:58:13

您的文件可能不是 UTF8 或类似的文件。

但是，如果您想破解修复程序，因为您对问题不感兴趣，而只是解决方案:)，那么请删除任何不是数字或小数点的内容。

String[] article = p.split(line);
Integer i = Integer.parseInt(article[0].replaceAll("[^0-9.]",""));

正则表达式并不完美（例如，它会影响 ...999...），但它会为您服务。

编辑：

我似乎没有正确阅读这个问题。如果它仅位于文件的开头，那么您所拥有的很可能是一个字节顺序标记，它用于告诉您该文件是否是 unicode 以及 UTF16/32 中的文件是小端还是大端字节序。您不需要经常看到它被使用。

http://unicode.org/faq/utf_bom.html#bom10

It could that your file is not UTF8 or something along those lines.

However if you want to hack a fix because you are not interested in the problem just a solution :) then strip out anything that isn't a digit or decimal point.

String[] article = p.split(line);
Integer i = Integer.parseInt(article[0].replaceAll("[^0-9.]",""));

The regular expression isn't perfect (it would affect ...999.... for example) but it will do for you.

EDIT:

I did not read the question properly it seems. If it is only at the start of the file then it is very likely that what you have is a byte order mark, which is used to tell you if the file is unicode and also in UTF16/32 whether it is is little endian or big endian. You don't need tend to see it used very often.

http://unicode.org/faq/utf_bom.html#bom10

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