在 Objective-C 中获取下周六的日期？

Question

在 iOS 的 Objective-C 中，如何获取今天之后第一个星期六的日期？

Answer 1

NSCalendar *gregorian = [[NSCalendar alloc]initWithCalendarIdentifier:NSGregorianCalendar];
NSDate *date = [NSDate date];
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit fromDate:date];
NSInteger todayWeekday = [weekdayComponents weekday];

enum Weeks {
    SUNDAY = 1,
    MONDAY,
    TUESDAY,
    WEDNESDAY,
    THURSDAY,
    FRIDAY,
    SATURDAY
};

NSInteger moveDays=SATURDAY-todayWeekday;
if (moveDays<=0) {
    moveDays+=7;
}

NSDateComponents *components = [NSDateComponents new];
components.day=moveDays;

NSCalendar *calendar=[[NSCalendar alloc] initWithCalendarIdentifier: NSGregorianCalendar];
NSDate* newDate = [calendar dateByAddingComponents:components toDate:date options:0];

NSLog(@"%@",newDate);

Answer 2

[NSDate dateWithNaturalLanguageString: @"next Saturday"]

---

编辑：从 OS X 10.9 和 iOS 8 开始，您可以执行以下操作：

NSCalendar *calendar = [NSCalendar currentCalendar];

NSDate *now = [NSDate date];
NSDateComponents *saturday = [[NSDateComponents alloc] init];
saturday.weekday = 7 /* Saturday */;

NSDate *nextSaturday = [calendar nextDateAfterDate:now matchingComponents:saturday options:0];

Answer 3

这将指导您完成操作日历日期的过程：

日历计算