Waf（构建工具）：像 Make 这样的 PHONY 目标？

发布于 2024-10-10 10:43:01 字数 401 浏览 6 评论 0原文

你如何设置一个始终被执行的目标（也许 Waf 称其为“命令”）？那就是像 Make 中的 PHONY 目标一样？

我正在使用 Waf 构建一个 Visual Studio 解决方案，我更希望由 Visual Studio 本身来管理其依赖项和重新编译。

目前我正在使用这个（简化的）定义：

def build(bld):
  bld( rule = "msbuild MySolution.sln /target:Build /property:CONFIGURATION=Release",
      source = "",
      target = "program.exe" )

但是，仅当“program.exe”丢失时才会调用“msbuild”。

谢谢。

原文

how do you set a target - maybe Waf calls them "commands" - to always be executed? That is to be like PHONY targets in Make?

I'm using Waf to build - among other things - a Visual Studio solution, whose dependencies and recompilation I would prefer to be managed by Visual Studio itself.

Currently I'm using this (simplified) definition:

def build(bld):
  bld( rule = "msbuild MySolution.sln /target:Build /property:CONFIGURATION=Release",
      source = "",
      target = "program.exe" )

However, "msbuild" gets called only when "program.exe" is missing.

Thanks.

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柏林苍穹下 2024-10-17 10:43:01

在 waf-users 邮件列表上问这个问题，解决方案是添加“always”参数：

def build(bld):
   bld( rule = "msbuild MySolution.sln /target:Build /property:CONFIGURATION=Release",
      target = "program.exe" ,
      always = True )

Asked this question on the waf-users mailing list and the solution is to add the "always" parameter:

def build(bld):
   bld( rule = "msbuild MySolution.sln /target:Build /property:CONFIGURATION=Release",
      target = "program.exe" ,
      always = True )

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