解析器 2.1 和 2.2

Question

我使用以下代码使用 getElementsByTagName 检索 XML 元素文本，

此代码在 2.2 中成功，在 2.1 中失败，

有什么想法吗？

URL metafeedUrl = new URL("http://x..../Y.xml")
URLConnection connection ;     
connection= metafeedUrl.openConnection();

HttpURLConnection  httpConnection = (HttpURLConnection)connection ;        
int resposnseCode= httpConnection.getResponseCode() ;

if (resposnseCode == HttpURLConnection.HTTP_OK) {

InputStream in = httpConnection.getInputStream();

DocumentBuilderFactory dbf ;
dbf = DocumentBuilderFactory.newInstance();

DocumentBuilder db = dbf.newDocumentBuilder();


// Parse the Earthquakes entry 
Document dom = db.parse(in);
Element docEle = dom.getDocumentElement();

//ArrayList<Album> Albums = new ArrayList<Album>();


/* Returns a NodeList of all descendant Elements with a given tag name, in document order.*/

NodeList nl = docEle.getElementsByTagName("entry");

if (nl!=null && nl.getLength() > 0) {        
   for (int i = 0; i < nl.getLength(); i++) {

Element entry = (Element)nl.item(i);

/* Now on every property in Entry **/

Element title =(Element)entry.getElementsByTagName("title").item(0);          

*Here i Get an Error*
String album_Title = title.getTextContent();

Element id =(Element)entry.getElementsByTagName("id").item(0);         
String album_id = id.getTextContent(); // 

Answer 1

API 7 (Android 2.1) 不支持 getTextContent()。它是在 API 8 (2.2) 中引入的。

假设服务器的结果是可预测的，您可以使用以下代码：

Node n = aNodeList.item(i);

String strValue = n.getFirstChild().getNodeValue();

// as opposed to the String strValue = n.getTextContent();

如果元素可能为空，那么您需要首先检查子计数。