C++模板部分特化错误

Question

下面的代码给了我一个编译错误：class Q64 is not a valid type for a templateconstant argument

template<int GRIDD, class T>
INLINE T grid_residue(T amount) {
  T rem = amount%(GRIDD);
  if (rem > GRIDD/2) rem -= GRIDD;
  return rem;
}


template<int GRIDD, Q64>
INLINE Q64 grid_residue(Q64 amount) {
  return Q64(grid_residue<GRIDD, int64_t>(to_int(amount)));
}

出了什么问题？我正在尝试将grid_residue专门用于Q64类。

更新：

更改了语法。现在出现错误错误：函数模板部分特化'grid_residue'不允许

template<int GRIDD>
INLINE Q64 grid_residue(Q64 amount) {
    return Q64(grid_residue<GRIDD, int>(to_int(amount)));
}

谢谢

Answer 1

函数不能部分特化！要么使用函数重载：template;内联 Q64 grid_residue(Q64 amount) 或将函数包装在类型中（可以部分专门化）。

Answer 2

您不能部分特化函数。

Answer 3

struct test
{

};

template<int GRIDD, class T>
T grid_residue(T amount) 
{
    std::cout << "template<int GRIDD, class T> T grid_residue(T amount)" << " GRIDD: " << GRIDD << std::endl;
    return T();
}


template<int GRIDD>
test grid_residue(test amount) 
{
    std::cout << "template<int GRIDD> test grid_residue(test amount)" << " GRIDD: " << GRIDD << std::endl;
    int inp = 0;
    grid_residue<GRIDD,int>(inp);
    return test();
}


int 
_tmain(int argc, _TCHAR* argv[])
{
    test amount;
    grid_residue<19>(amount);
    std::string inValue;
    grid_residue<19>(inValue);
}

编译/链接正常（VS2010）。