awk 并多次提取特定字段

发布于 2024-10-10 01:17:30 字数 882 浏览 2 评论 0原文

我有很多包含变量的文件，就像

{$var1} some text {$var2} some other text

我想将它们交给 awk 以便 awk 提取它们并给出如下结果：

file_name.htm - 8 : {$title}
file_name.htm - 10 : {$css_style}
file_name.htm - 33 : {$img_carte_image_02_over}

对于这个 awk 脚本来说这是小菜一碟：

#!/usr/bin/gawk -f
BEGIN { }
match($0, /({.*\$.+})/, tab) {
  for (x=1; tab[x]; x++) {
    print FILENAME" - "FNR" : "substr($0, tab[x, "start"], tab[x, "length"])
  }
}
END { }

我这样称呼它：

find website/ | grep -E '(html|htm)$' | xargs ./myh.sh | more

除非多个变量位于同一行，否则一切正常。在这种情况下，我得到：

file_name.htm - 59 : {$var1}<br/>{$var2}

而我想要：

file_name.htm - 59 : {$var1}
file_name.htm - 59 : {$var2}

知道我可以/应该做什么吗？当然，如果您有其他解决方案（使用 sed 或其他），对我来说没问题！

多谢！

原文

I've got many files with variables in them like

{$var1} some text {$var2} some other text

I'd like to give them to awk so that awk extracts them and gives a result like this:

file_name.htm - 8 : {$title}
file_name.htm - 10 : {$css_style}
file_name.htm - 33 : {$img_carte_image_02_over}

This is a piece of cake with this awk script:

#!/usr/bin/gawk -f
BEGIN { }
match($0, /({.*\$.+})/, tab) {
  for (x=1; tab[x]; x++) {
    print FILENAME" - "FNR" : "substr($0, tab[x, "start"], tab[x, "length"])
  }
}
END { }

I'm calling it like this:

find website/ | grep -E '(html|htm)
Everything works fine except when multiples variables are on the same line. In this case I get:
file_name.htm - 59 : {$var1}<br/>{$var2}

whereas I want:
file_name.htm - 59 : {$var1}
file_name.htm - 59 : {$var2}

Any idea how I could/should do?

Of course if you have another solution (with sed or whatever) it's ok for me!
Thanks a lot!
 | xargs ./myh.sh | more

Everything works fine except when multiples variables are on the same line. In this case I get:

whereas I want:

Any idea how I could/should do?
Of course if you have another solution (with sed or whatever) it's ok for me!

Thanks a lot!

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物价感观 2024-10-17 01:17:30

试试这个：

awk '{
    line=$0; 
    while (match(line,/({[^$]*\$[^}]+})/)){
        print FILENAME,"-",FNR,":",substr(line,RSTART,RLENGTH);
        line=substr(line,RSTART+RLENGTH+1)
    }
}'

当 match() 返回 0 时，即 line 不包含任何其他“{foo$bar}”字符串时，循环结束；我使用 substr() 删除已扫描匹配项的行部分。

Try this one:

awk '{
    line=$0; 
    while (match(line,/({[^$]*\$[^}]+})/)){
        print FILENAME,"-",FNR,":",substr(line,RSTART,RLENGTH);
        line=substr(line,RSTART+RLENGTH+1)
    }
}'

The cycle ends when match() returns 0, that is when line doesn't contain any other "{foo$bar}" strings; I used substr() to remove the part of the line which has been already scanned for matches.

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