如何防止 const 引用参数的临时实现
我需要编写一个类，其构造函数采用对对象的常量引用并将其存储在本地。
为了避免我可以预见的最常见错误，我只想接受对非临时的引用（即：对左值的引用）。
如何编写一个仅接受非临时常量引用的函数？
当然，即使是非临时引用也可能超出范围，从而破坏我的班级行为，但我相信通过禁止临时引用我将避免大多数错误。
I need to write a class whose constructor takes a constant reference to a object and stores it locally.
In order to avoid most common mistakes I can foresee, I'd like to only accept references to non-temporary (ie: references to lvalues).
How can I write a function that takes constant references to non-temporary only?
Of course even a non-temporary could go out of scope and thus break my class behavior, but I believe that by disallowing temporary references I will avoid most mistakes.
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如果您要存储引用并需要在构造函数完成后使用它，那么构造函数最好采用指针：
这样，几乎可以保证您不会有一个指向临时对象的指针（除非
X做了一些非常愚蠢的事情，比如重载一元&以返回this）。如果构造函数采用指针，则类的用户也更清楚地知道他们需要注意传递给构造函数的
X对象的生命周期。If you are going to store a reference and need to use it after the constructor has completed, it's probably best for the constructor to take a pointer:
This way, it's pretty much guaranteed that you won't have a pointer to a temporary (unless
Xdoes something really dumb, like overloading the unary&to returnthis).If the constructor takes a pointer, it's also clearer to users of the class that they need to pay attention to the lifetime of the
Xobject they pass to the constructor.