C# Windows 窗体设计时窗体构造函数未调用？
在设计视图中打开表单时是否不调用表单的构造函数？为什么不呢？我可以以某种方式强制调用它吗？ 我通过在构造函数中显示 MessageBox 来测试它，并且仅显示表单基本类型（另一种表单）的构造函数中的 MessageBox...
Is the constructor of a form not called upon opening the form in design view? Why not? Can I somehow force it to be called?
I tested it by showing a MessageBox in the constructor, and only the MessageBox from the constructor of the form's base type (another form) is shown...
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此行为是设计使然。 Visual Studio 中的表单设计器无法实例化正在设计的类，而是实例化其直接父类。没有办法改变这种行为。如果您需要在设计时执行某些逻辑，则必须创建一个单独的祖先来封装该逻辑并从中继承。
这也是为什么为了能够使用设计器，您不能从抽象或泛型类继承表单的原因。
This behavior is by design. The form designer in Visual Studio cannot instantiate the class being designed — instead, it instatiates its immediate parent. There is no way to change this behavior. If you need some logic to be executed during design time, you have to create a separate ancestor encapsulating that logic and inherit from it.
That's also the reason why in order to be able to use the designer you cannot inherit a form from an abstract or generic class.