通过 Web 服务将文件（至少 11 个文件）从文件夹发送到 Android 应用程序

Question

我陷入了这种境地，请帮助我。

我的问题是我想使用网络服务将文件（总共 11 个 PDF 文件）发送到 Android 应用程序。

我用下面的代码尝试了它。创建 Web 服务的主类

public class MultipleFilesImpl implements MultipleFiles {

public FileData[] sendPDFs() {
    FileData fileData = null;
    // List<FileData> filesDetails = new ArrayList<FileData>();
    File fileFolder = new File(
            "C:/eclipse/workspace/AIPWebService/src/pdfs/");
    // File fileTwo = new File(
    // "C:/eclipse/workspace/AIPWebService/src/simple.pdf");

    File sendFiles[] = fileFolder.listFiles();
    // sendFiles[0] = fileOne;
    // sendFiles[1] = fileTwo;

    DataHandler handler = null;
    char[] readLine = null;
    byte[] data = null;
    int offset = 0;
    int numRead = 0;
    InputStream stream = null;
    FileOutputStream outputStream = null;
    FileData[] filesData = null;
    try {
        System.out.println("Web Service Called Successfully");

        for (int i = 0; i < sendFiles.length; i++) {
            handler = new DataHandler(new FileDataSource(sendFiles[i]));
            fileData = new FileData();
            data = new byte[(int) sendFiles[i].length()];
            stream = handler.getInputStream();
            while (offset < data.length
                    && (numRead = stream.read(data, offset, data.length
                            - offset)) >= 0) {
                offset += numRead;
            }
            readLine = Base64Coder.encode(data);
            offset = 0;
            numRead = 0;
            System.out.println("'Reading File............................");
            System.out.println("\n");
            System.out.println(readLine);
            System.out.println("Data Reading Successful");

            fileData.setFileName(sendFiles[i].getName());
            fileData.setFileData(String.valueOf(readLine));

            readLine = null;
            System.out.println("Data from bean " + fileData.getFileData());

            outputStream = new FileOutputStream("D:/"
                    + sendFiles[i].getName());

            outputStream.write(Base64Coder.decode(fileData.getFileData()));

            outputStream.flush();
            outputStream.close();
            stream.close();
            // FileData fileDetails = new FileData();
            // fileDetails = fileData;
            // filesDetails.add(fileData);
            filesData = new FileData[(int) sendFiles[i].length()];
        }
        // return fileData;
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } catch (Exception e) {
        e.printStackTrace();
    }

    return filesData;
}

}

还有接口 MultipleFiles：-

public interface MultipleFiles extends Remote {
    public FileData[] sendPDFs() throws FileNotFoundException, IOException,
            Exception;
}

这里我发送一个bean“文件数据”数组，具有属性即。文件数据与文件名。 FileData- 包含编码的文件数据。 FileName-编码的文件名。

The Bean:- (FileData)

public class FileData {
    private String fileName;
    private String fileData;

    public String getFileName() {
        return fileName;
    }

    public void setFileName(String fileName) {
        this.fileName = fileName;
    }

    public String getFileData() {
        return fileData;
    }

    public void setFileData(String string) {
        this.fileData = string;
    }

}

当尝试下面的代码时，android DDMS 会给出内存不足的异常：当我尝试发送两个文件时，仅创建第一个文件。

public class PDFActivity extends Activity {
    private final String METHOD_NAME = "sendPDFs";
    private final String NAMESPACE = "http://webservice.uks.com/";
    private final String SOAP_ACTION = NAMESPACE + METHOD_NAME;
    private final String URL = "http://192.168.1.123:8080/AIPWebService/services/MultipleFilesImpl";

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);

        TextView textViewOne = (TextView) findViewById(R.id.textViewOne);

        try {
            SoapObject soapObject = new SoapObject(NAMESPACE, METHOD_NAME);

            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                    SoapEnvelope.VER11);
            envelope.setOutputSoapObject(soapObject);

            textViewOne.setText("Web Service Started");
            AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);

            httpTransport.call(SOAP_ACTION, envelope);

            // SoapObject result = (SoapObject) envelope.getResponse();
            Object result = envelope.getResponse();
            Log.i("Result", result.toString());
            // String fileName = result.getProperty("fileName").toString();
            // String fileData = result.getProperty("fileData").toString();

            // Log.i("File Name", fileName);
            // Log.i("File Data", fileData);

            // File pdfFile = new File(fileName);


            // FileOutputStream outputStream =
            // openFileOutput(pdfFile.toString(),
            // MODE_PRIVATE);

            // outputStream.write(Base64Coder.decode(fileData));
            Log.i("File", "File Created");
            // textViewTwo.setText(result);
            // Object result = envelope.getResponse();
            // FileOutputStream outputStream = openFileOutput(name, mode)

        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

请帮助解释或更改我的代码。 提前致谢。

Answer 1

我自己得到了这个问题的答案。

我使用 kSoap2 api 2.4 版本面临的主要问题是我无法获取复杂的对象（在我的例子中是 bean 数组）

然后我将我的代码从这个（使用版本 2.4）更改

try {
            SoapObject soapObject = new SoapObject(NAMESPACE, METHOD_NAME);

            SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                    SoapEnvelope.VER11);
            envelope.setOutputSoapObject(soapObject);

            textViewOne.setText("Web Service Started");
            AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL);

            httpTransport.call(SOAP_ACTION, envelope);

            // SoapObject result = (SoapObject) envelope.getResponse();
            Object result = envelope.getResponse();
            Log.i("Result", result.toString());
            // String fileName = result.getProperty("fileName").toString();
            // String fileData = result.getProperty("fileData").toString();

            // Log.i("File Name", fileName);
            // Log.i("File Data", fileData);

            // File pdfFile = new File(fileName);


            // FileOutputStream outputStream =
            // openFileOutput(pdfFile.toString(),
            // MODE_PRIVATE);

            // outputStream.write(Base64Coder.decode(fileData));
            Log.i("File", "File Created");
            // textViewTwo.setText(result);
            // Object result = envelope.getResponse();
            // FileOutputStream outputStream = openFileOutput(name, mode)

        } catch (Exception e) {
            e.printStackTrace();
        }

为这个代码（使用版本 2.5） .1):-

    try {
        SoapObject soapObject = new SoapObject(NAMESPACE, METHOD_NAME);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER11);

        envelope.setOutputSoapObject(soapObject);

        HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
        androidHttpTransport.call(SOAP_ACTION, envelope);

        SoapObject result = (SoapObject) envelope.bodyIn;

        for (int i = 0; i < result.getPropertyCount(); i++) {
            SoapObject object = (SoapObject) result.getProperty(i);

            Log.i("File Data", object.getProperty("fileData").toString());
            Log.i("File Name", object.getProperty("fileName").toString());

            pdfFiles = new File(object.getProperty("fileName").toString());
            outputStream = openFileOutput(pdfFiles.toString(), MODE_PRIVATE);
            outputStream.write(Base64Coder.decode(object.getProperty(
                    "fileData").toString()));
        }

        outputStream.flush();
        outputStream.close();
        Log.d("File Creation Message", "Files Created Succesfully");
    } catch (SoapFault fault) {
        fault.printStackTrace();
    } catch (XmlPullParserException e) {
        e.printStackTrace();
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } catch (Exception e) {
        e.printStackTrace();
    } finally {
        if (outputStream != null) {
            outputStream = null;
        }
    }

因此我得到了解决方案。

主要帮助是通过此问题的第 24 期：- 如果您遇到此类问题，请阅读该内容。链接问题-24