泛型和继承问题
我很想说这个问题与我的一般架构有关，但无论哪种方式，作为示例显示可能比描述更容易。
public class AppUserBase
{
}
public class AppUserAbc : AppUserBase
{
}
public class ManagerBase<T> where T : AppUserBase
{
protected AppUserCollection<T> _users = new AppUserCollection<T>();
}
public class ManagerAbc : ManagerBase<AppUserAbc>
{
}
public static class Program
{
public static void Main()
{
ManagerAbc x = new ManagerAbc();
DoSomething(x); //fails
}
public static void DoSomething<M,U>(ManagerBase<AppUserBase> manager) where M : ManagerBase<U> where U : AppUserBase
{
//do something!
}
}
我希望我正在尝试做的事情很容易看到，并且我应该做的事情更容易向我解释:-)。
I'm tempted to say this problem is with my general architecture but either way it's probably easier to show as an example than it would be to describe.
public class AppUserBase
{
}
public class AppUserAbc : AppUserBase
{
}
public class ManagerBase<T> where T : AppUserBase
{
protected AppUserCollection<T> _users = new AppUserCollection<T>();
}
public class ManagerAbc : ManagerBase<AppUserAbc>
{
}
public static class Program
{
public static void Main()
{
ManagerAbc x = new ManagerAbc();
DoSomething(x); //fails
}
public static void DoSomething<M,U>(ManagerBase<AppUserBase> manager) where M : ManagerBase<U> where U : AppUserBase
{
//do something!
}
}
I hope what I'm trying to do is easy to see and what I should be doing is even easier to explain to me :-).
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这是因为您有两个类型参数，但方法签名中只有一个，因此它无法推断出两者。另一个则不需要。将方法签名更改为：
It's because you have two type parameters but only one is in the method signature, so it can't infer both. The other is not needed. Change your method signature to:
你可能知道，他们需要工作。原因是
ManagerAbc不是ManagerBase类型。通用部分属于同一类型并没有帮助。您可以尝试更改为：That want work, as you probably know. The reason is that
ManagerAbcis not of typeManagerBase<AppUserBase>. It doesn't help that the generic part is of the same type. You could try to change to: