MySQL 数据库错误:操作数应包含 1 列

发布于 2024-10-09 00:35:06 字数 969 浏览 1 评论 0原文

这是声明。目的并不重要,只是我需要能够判断发布规则属于什么类型的对象。谢谢!

select case(select count(mediaitemguid) from mediaitempublicationrules where publicationruleguid = '<snip>')
       when 0 then case(select count(catalogguid) from catalogpublicationrules where publicationruleguid = '<snip>')
           when 0 then case(select count(domainguid) from domaindefaultpublicationrules where publicationruleguid = '<snip>')
              when 0 then null
             else (select 'Domain', domainguid from domaindefaultpublicationrules where publicationruleguid = '<snip>')
             end
           else (select 'Catalog', catalogguid from catalogpublicationrules where publicationruleguid = '<snip>')
           end
       else (select 'MediaItem', mediaitemguid from mediaitempublicationrules where publicationruleguid = '<snip>')
       end;

编辑:更多的澄清...这工作得很好,直到我将这些“域”“目录”“媒体项”条目放入 else 语句的嵌套选择中。这可能相当简单,只是之前没有遇到过这个错误

Here is the statement. The purpose isn't really important, just that I need to be able to tell what type of object the publication rule belongs to. Thanks!

select case(select count(mediaitemguid) from mediaitempublicationrules where publicationruleguid = '<snip>')
       when 0 then case(select count(catalogguid) from catalogpublicationrules where publicationruleguid = '<snip>')
           when 0 then case(select count(domainguid) from domaindefaultpublicationrules where publicationruleguid = '<snip>')
              when 0 then null
             else (select 'Domain', domainguid from domaindefaultpublicationrules where publicationruleguid = '<snip>')
             end
           else (select 'Catalog', catalogguid from catalogpublicationrules where publicationruleguid = '<snip>')
           end
       else (select 'MediaItem', mediaitemguid from mediaitempublicationrules where publicationruleguid = '<snip>')
       end;

EDIT: a little more clarification...this worked just fine until I put those 'Domain' 'Catalog' 'MediaItem' entries into the nested selects on the else statements. It's probably something fairly simple, just haven't run into that error before

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爱的十字路口 2024-10-16 00:35:06

该错误表明您应该返回单列而不是两列

解决方法之一是使用 concat_ws 类似

select concat_ws(':', 'Domain', domainguid') ... <-- ':' is the delimiter

The error indicate you should return single column instead of two

One way to fix is to use concat_ws like

select concat_ws(':', 'Domain', domainguid') ... <-- ':' is the delimiter
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