Zend Framework：如何呈现不同的动作？

发布于 2024-10-09 00:00:29 字数 1444 浏览 11 评论 0原文

我有两个基本相同的操作，但需要不同的 URL。通常我会使用 _forward() 来呈现其他操作：

class MyController extends Zend_Controller_Action
{
    public function actionOneAction()
    {
        $this->_forward('action-two');
    }

    public function actionTwoAction()
    {
        $this->view->foobar = 'foobar';
    }
}

但是，我有一些代码发生在 preDispatch() 中，我只想执行一次：

class MyController extends Zend_Controller_Action
{
    public function preDispatch()
    {
        //execute this only once before actionOne or actionTwo, but not both
    }

    public function actionOneAction()
    {
        $this->_forward('action-two'); //this won't work because preDispatch() will get called a second time
    }

    public function actionTwoAction()
    {
        $this->view->foobar = 'foobar';
    }
}

所以我我想也许我可以直接调用该函数，如下所示：

class MyController extends Zend_Controller_Action
{
    public function preDispatch()
    {
        //execute this only once before actionOne or actionTwo, but not both
    }

    public function actionOneAction()
    {
        $this->actionTwoAction(); //execute the same code as actionTwoAction()
    }

    public function actionTwoAction()
    {
        $this->view->foobar = 'foobar';
    }
}

但现在 Zend Framework 抱怨无法找到 action-one.phtml 视图脚本。我不想渲染 actionOne 的视图脚本。我想渲染actionTwo 的视图脚本。我需要做什么？

原文

I have two actions that are essentially identical, but need different URLs. Normally I would use _forward() to render the other action:

class MyController extends Zend_Controller_Action
{
    public function actionOneAction()
    {
        $this->_forward('action-two');
    }

    public function actionTwoAction()
    {
        $this->view->foobar = 'foobar';
    }
}

However, I have some code the is happening in preDispatch() that I only want to execute once:

class MyController extends Zend_Controller_Action
{
    public function preDispatch()
    {
        //execute this only once before actionOne or actionTwo, but not both
    }

    public function actionOneAction()
    {
        $this->_forward('action-two'); //this won't work because preDispatch() will get called a second time
    }

    public function actionTwoAction()
    {
        $this->view->foobar = 'foobar';
    }
}

So I thought maybe I could simply call the function directly, like this:

class MyController extends Zend_Controller_Action
{
    public function preDispatch()
    {
        //execute this only once before actionOne or actionTwo, but not both
    }

    public function actionOneAction()
    {
        $this->actionTwoAction(); //execute the same code as actionTwoAction()
    }

    public function actionTwoAction()
    {
        $this->view->foobar = 'foobar';
    }
}

But now Zend Framework is complaining about not being able to find the action-one.phtml view script. I don't want to render actionOne's view script. I want to render actionTwo's view script. What do I need to do?

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鹿童谣 2024-10-16 00:00:29

使用 render() 似乎可以解决问题：

public function actionOneAction()
{
    $this->actionTwoAction(); //execute the same code as actionTwoAction()
    $this->render('action-two'); //renders the same view as actionTwoAction()
}

Using render() seems to do the trick:

public function actionOneAction()
{
    $this->actionTwoAction(); //execute the same code as actionTwoAction()
    $this->render('action-two'); //renders the same view as actionTwoAction()
}

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