我如何使这个 preg_match() reg 表达式忽略空格？

发布于 2024-10-08 23:18:50 字数 434 浏览 7 评论 0原文

我有这个正则表达式：

if(preg_match("/^(\\d+)(,)(\\d+)$/") ) { ... }

它测试用户是否输入了一对用逗号分隔的数字（例如 120,80）。我已经让那部分工作正常了。不过，我预计用户可能会意外地在任何字符之间输入空格。我想让表达式忽略所有空白字符，无论它们出现在模式中的位置。我已经尝试过这个：

if(preg_match("/x^(\\d+)(,)(\\d+)$/x") ) { ... }

还有这个：

if(preg_match("/(^(\\d+)(,)(\\d+))$/x") ) { ... }

但似乎没有任何效果。任何见解将不胜感激。顺便说一句，我仍在学习这些东西，所以请考虑到这一点！谢谢。：D

原文

I have this regular expression:

if(preg_match("/^(\\d+)(,)(\\d+)$/") ) { ... }

which tests that the user has entered a pair of numbers separated by a comma (e.g. 120,80). I've got that part working properly. However I anticipate that users may accidentally enter white space between any of the characters. I would like to make the expression ignore ALL white space characters, no matter where they occur in the pattern. I've tried this:

if(preg_match("/x^(\\d+)(,)(\\d+)$/x") ) { ... }

And also this:

if(preg_match("/(^(\\d+)(,)(\\d+))$/x") ) { ... }

But nothing seems to work. Any insights would be greatly appreciated. BTW I'm still learning this stuff so take that into account! Thanks. :D

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对风讲故事 2024-10-15 23:18:50

您可以在进行正则表达式匹配之前删除空格。

$input = str_replace(" ", "", $input);

You might just strip whitespace before you do your regex match.

$input = str_replace(" ", "", $input);

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似梦非梦 2024-10-15 23:18:50

尝试：

if(preg_match("/^\s*\d+\s*,\s*\d+\s*$/",$input) ) { 
   // $input has two numbers separated by a comma and may have whitespace
   // around the number and/or around the comma.
}

Try:

if(preg_match("/^\s*\d+\s*,\s*\d+\s*$/",$input) ) { 
   // $input has two numbers separated by a comma and may have whitespace
   // around the number and/or around the comma.
}

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~没有更多了~