将QListView的双击事件与PyQt4中的方法连接
我有一个 PyQt QListView 对象，我想要一个在双击它时运行的方法。这应该是微不足道的，但它似乎不起作用。我的代码如下：
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
lb = QListView()
self.connect(lb, SIGNAL('doubleClicked()'), self.someMethod)
grid = QGridLayout()
grid.addWidget(lb, 0, 0)
centralWidget.setLayout(grid)
def someMethod(self):
print "It happened!"
我也尝试过 clicked() 和 entered() 方法，但它们也不起作用。这些事件均在此处的文档中列出。
I’ve got a PyQt QListView object, and I want a method to run when it is double-clicked. This should be trivial, but it doesn't seem to work. My code is as follows:
class MainWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
lb = QListView()
self.connect(lb, SIGNAL('doubleClicked()'), self.someMethod)
grid = QGridLayout()
grid.addWidget(lb, 0, 0)
centralWidget.setLayout(grid)
def someMethod(self):
print "It happened!"
I’ve tried clicked() and entered() methods too, but they do not work either. These events are all listed in the documentation here.
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它似乎有效，如果：
被替换为新语法：
后者也更加优雅。然而，我仍然不知道为什么原始语法不起作用。
It seems to work if:
Is replaced with the new syntax of:
The latter is much more elegant too. I still do not know why the original syntax did not work, however.
如果您使用以下方法，它也将起作用：
检查 pyqt 参考，然后按原样复制并粘贴信号。
我知道你已经解决了。但我认为了解不止一种方法会更好。
It will also work if you use:
check the pyqt reference, then copy and paste the signal as is.
I know you already solved it. but I think knowing more than one method will be better.
itemDoubleClicked是由QListWidget而不是QListView发出的信号。我测试了 Moayyad Yaghi 的建议，它至少在带有 python 2.5 的 Qt 4 上对我不起作用，但是 lb.doubleClicked.connect(self.someMethod) 工作得很好。
itemDoubleClickedis a signal emitted byQListWidgetand notQListView. I tested Moayyad Yaghi's suggestion and it did not work for me at least on Qt 4 with python 2.5Though,
lb.doubleClicked.connect(self.someMethod)works perfectly fine.