为什么这个变量总是返回true？
我正在尝试编写一个登录脚本。设置登录会话变量后，在主页上运行 isLoggedIn 函数。问题是变量 $loggedIn 总是返回 true。有人可以帮忙吗？
function validateUser($user)
{
if(isset($user)){
session_regenerate_id ();//this is a security measure
$_SESSION['logged'] = 1;
$_SESSION['userid'] = $user;}
}
//Validates Login
function isLoggedIn()
{
if($_SESSION['logged'] = 1)
return true;
return false;
}
$loggedIn = isLoggedIn();
if($loggedIn){ SHOW CONTENT FOR LOGGED IN USERS }
else { show content for users not logged in }
I am trying to write a login script. After logging in a session variable is set, and on the main page, the isLoggedIn function is run. The problem is, that the variable $loggedIn is always returning true. Can someone help?
function validateUser($user)
{
if(isset($user)){
session_regenerate_id ();//this is a security measure
$_SESSION['logged'] = 1;
$_SESSION['userid'] = $user;}
}
//Validates Login
function isLoggedIn()
{
if($_SESSION['logged'] = 1)
return true;
return false;
}
$loggedIn = isLoggedIn();
if($loggedIn){ SHOW CONTENT FOR LOGGED IN USERS }
else { show content for users not logged in }
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评论（4）
不是这个 if($_SESSION['logged'] = 1)
这是正确的 -> if($_SESSION['已记录'] == 1)
NOT THIS if($_SESSION['logged'] = 1)
THIS is correct -> if($_SESSION['logged'] == 1)
您正在使用赋值运算符
=而不是条件运算符==。它应该是：
赋值
=的结果是右侧表达式，即 1，在本例中始终为 true。 :)You are using the assignment operator
=instead of a conditional operator==.It's supposed to be:
The result of an assignment
=is the right hand side expression, which is 1, which is always true in this case. :)这是因为您将 $_SESSION['logged'] 设置为单个等于。使用双等号代替：
it's because you're setting $_SESSION['logged'] with the single equals. Use a double equals instead:
函数 isLoggedIn()
{
if($_SESSION['logged'] = 1)//将值'1'赋给$_SESSION['logged']，因此在这个if条件下，它检查$_SESSION['logged']是否有任何值，其中对于所有情况都适用（有效/无效）
返回真；
返回假；
}
$loggedIn = isLoggedIn();/$loggedIn 的值始终为 true 将
if($_SESSION['logged'] = 1) 更改为 if($_SESSION['logged'] == 1)
function isLoggedIn()
{
if($_SESSION['logged'] = 1)//assigned value '1' to $_SESSION['logged'] so in this if condition it is checking if there is any value is $_SESSION['logged'], which will be true for all the cases (valid/invalid)
return true;
return false;
}
$loggedIn = isLoggedIn();/those the value for $loggedIn will be always true
change the if($_SESSION['logged'] = 1) to if($_SESSION['logged'] == 1)