使用 tel: url 发起呼叫 - 但需要插入特殊字符 #
我需要发起一个调用，该调用还输入一个由 # 分隔的 id
问题是，一旦我插入这个特殊字符，该方法就不会触发（正如文档中所解释的，我知道）
另外 stringByAddingPercentEscapesUsingEncoding 不会改变任何东西。
有解决方法吗？我可以发送/模拟击键吗？
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:12345#2"]]; <- 因为 # 它不会触发。
非常感谢....
Possible Duplicate:
How to use tel: with * (star, asterisk) or # (hash, pound) on iOs?
I need to initiate a call which also enters an id separated by #
The problem is that as soon as I insert this special character the method does not fire (as explained in the doc, I know)
Also stringByAddingPercentEscapesUsingEncoding does not change anything.
Is there a workaround? Can I send /simulate key strokes ?
[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel:12345#2"]]; <- because of the # it does not fire.
Thanks very much....
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CTCallDialWithID(@"12345#2", -1);
并与 CoreTelephony 链接。
CTCallDialWithID(@"12345#2", -1);
and link with CoreTelephony.
我认为这是不可能的。在另一个论坛上，有人向苹果询问了这个问题，但从未得到答复
I think it's not possible. And in another forum someone asked Apple about that, but never get an answer back
根据 RFC2806 你有一个“拨号后”部分这似乎可以让你做你想做的事。
尝试：
According to RFC2806 you've got a 'post-dial' part that seemingly let's you do what you want.
Try: