如何将删除器传递给由shared_ptr持有的同一类中的方法

发布于 2024-10-08 15:46:33 字数 810 浏览 3 评论 0原文

我有几个来自第三方库的类，类似于 StagingConfigDatabase 类，它需要在创建后销毁。我正在为 RAII 使用shared_ptr，但更愿意使用单行代码创建shared_ptr，而不是像我的示例所示使用单独的模板函子。也许使用 lambda 表达式？或绑定？

struct StagingConfigDatabase
{
  static StagingConfigDatabase* create();
  void destroy();
};

template<class T>
    struct RfaDestroyer
    {
        void operator()(T* t)
        {
            if(t) t->destroy();
        }
    };

    int main()
    {
      shared_ptr<StagingConfigDatabase> pSDB(StagingConfigDatabase::create(), RfaDestroyer<StagingConfigDatabase>());
    return 1;
    }

我正在考虑类似的事情：

shared_ptr<StagingConfigDatabase> pSDB(StagingConfigDatabase::create(), [](StagingConfigDatabase* sdb) { sdb->destroy(); } );

但这不能编译:(

救命！

原文

I have several classes from 3rd party library similar to the class, StagingConfigDatabase, which requires to be destroyed after it is created. I am using a shared_ptr for RAII but would prefer to create the shared_ptr using a single line of code rather than using a seperate template functor as my example shows. Perhaps using lambdas? or bind?

struct StagingConfigDatabase
{
  static StagingConfigDatabase* create();
  void destroy();
};

template<class T>
    struct RfaDestroyer
    {
        void operator()(T* t)
        {
            if(t) t->destroy();
        }
    };

    int main()
    {
      shared_ptr<StagingConfigDatabase> pSDB(StagingConfigDatabase::create(), RfaDestroyer<StagingConfigDatabase>());
    return 1;
    }

I was considering something like:

shared_ptr<StagingConfigDatabase> pSDB(StagingConfigDatabase::create(), [](StagingConfigDatabase* sdb) { sdb->destroy(); } );

but that doesn't compile :(

Help!

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

翻身的咸鱼 2024-10-15 15:46:33

我假设 create 在 StagingConfigDatabase 中是静态的，因为如果没有它，您的初始代码将无法编译。关于销毁，您可以使用简单的 std::mem_fun< /a>：

#include <memory>

boost::shared_ptr<StagingConfigDatabase> pSDB(StagingConfigDatabase::create(), std::mem_fun(&StagingConfigDatabase::destroy));

I'll assume that create is static in StagingConfigDatabase because your initial code wouldn't compile without it. Regarding destruction, you can use a simple std::mem_fun :

#include <memory>

boost::shared_ptr<StagingConfigDatabase> pSDB(StagingConfigDatabase::create(), std::mem_fun(&StagingConfigDatabase::destroy));

回复收藏 0 原文

陈甜 2024-10-15 15:46:33

你使用什么编译器？它是否支持 lambda 等 C++0x 功能？以下内容（与您的示例基本相同）在 MSVC 2010 下编译并工作正常：

#include <iostream>
#include <memory>

struct X
{
    static X *create()
    {
        std::cout << "X::create\n";
        return new X;
    }

    void destroy()
    {
        std::cout << "X::destroy\n";
        delete this;
    }
};

int main()
{
    auto p = std::shared_ptr<X>(X::create(), [](X *p) { p->destroy(); });
    return 0;
}

“工作正常”，我的意思是“输出 X::create 后跟 X::destroy”。

What compiler are you using? Does it support C++0x features like lambdas? The following (which is basically the same as your example) compiles and works fine for me under MSVC 2010:

#include <iostream>
#include <memory>

struct X
{
    static X *create()
    {
        std::cout << "X::create\n";
        return new X;
    }

    void destroy()
    {
        std::cout << "X::destroy\n";
        delete this;
    }
};

int main()
{
    auto p = std::shared_ptr<X>(X::create(), [](X *p) { p->destroy(); });
    return 0;
}

By "works fine", I mean "outputs X::create followed by X::destroy".

回复收藏 0 原文

~没有更多了~