如果 ServerSocket 接受连接，它会继续等待进一步的请求吗？
我正在使用 ServerSocket(8080,1,InetAddress.getByName("127.0.0.1"))
现在在accept方法中我从SS获取Socket。我的问题是，一旦我获得 Socket 并继续处理，如果在处理完成之前收到另一个请求，ServerSocket 会接受该请求吗？
更新：我有一个 while 循环，如下面的答案所示，它接受连接。我的疑问是，对于这个实例化，如果我继续处理我的请求，并且如果另一个连接请求进来，它会被接受吗？
I am using
ServerSocket(8080,1,InetAddress.getByName("127.0.0.1"))
Now in the accept method I obtain the Socket from SS. My question is once I get the Socket and continue with my processing if another request comes in before my processing is complete, will ServerSocket accept that request?
Update: I have a while loop as in the answer below which accepts the connection. My doubt is with this instantiation if I continue with processing of my request and if another connection request comes in will it be accepted?
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如果您再次调用accept方法，它只会接受请求，因此如果您想接受多个连接，您可以有一个仅旋转调用accept方法的线程，如下所示：
It will only accept requests if you call the accept method again, so if you wanted to accept multiple connections, you could have a thread that just spins calling the accept method, like so:
由于您构建的 ServerSocket 的积压为 1，因此一次可能只有一个未处理（不是
accept()ed）的连接。所有额外的连接尝试都将被拒绝。换句话说，backlog 参数指定存储连接的队列的大小，直到它们被程序接受为止。Since you have constructed this ServerSocket with a backlog of 1 there may be only one unprocessed (not
accept()ed) connection at a time. All additional connection attempts will be refused. In other words, the backlog parameter specifies the size of a queue which stores connections until they are accepted by your program.它将处于待处理状态，直到您再次调用
accept为止。如果您收到多个请求，则最多将保留一定数量的请求，直到您接受。该限制是服务器套接字的队列大小。It will be in a pending state until you call
acceptagain. If you get multiple requests coming in, then up to a certain number will be kept queued until youaccept. That limit is the queue size of the Server Socket.