如何对两个对象使用集合方法(removeAll()和retainAll())。 (对象是父子关系)

发布于 2024-10-08 10:33:08 字数 2385 浏览 4 评论 0原文

我预计结果如下,但实际上没有。我想知道如何显示两个集合之间的差异。 (对象是父子关系) 在这种情况下,我可以使用标准方法(如removeAll())还是您可以推荐另一种方法(如使用apache-commons)。谢谢。

CONSTRAINT
------------------------------
1.Item.class is unmodifiable(eg. I can not add equals method)
2.If id is same between two objects, they are assumed as same things.
------------------------------

EXPECTED
------------------------------
removed object are:
2
same object are:
1
3
add object are:
4
------------------------------

ACTUAL
------------------------------
removed object are:
1
2
3
same object are:
add object are:
1
3
4
------------------------------

package com.javastudy;

import java.util.ArrayList;
import java.util.List;

public class CollectionCompareToObjects {

    public static void main(String[] args) {

        List<Item> before = new ArrayList<Item>();
        List<ItemEx> after = new ArrayList<ItemEx>();

        before.add(new Item(1L));
        before.add(new Item(2L)); // delete
        before.add(new Item(3L));

        after.add(new ItemEx(1L));
        after.add(new ItemEx(3L));
        after.add(new ItemEx(4L)); // added

        List<Item> removed = new ArrayList<Item>(before);
        removed.removeAll(after);

        System.out.println("removed objects are:");
        for(Item item : removed){
            System.out.println(item.getId());
        }

        List<Item> same = new ArrayList<Item>(before);
        same.retainAll(after);

        System.out.println("same objects are:");
        for(Item item : same){
            System.out.println(item.getId());
        }

        List<Item> added = new ArrayList<Item>(after);
        added.removeAll(before);

        System.out.println("add objects are:");
        for(Item item : added){
            System.out.println(item.getId());
        }

    }

}


package com.javastudy;

public class Item {

    private Long id;

    public Item(Long id) {
        this.id = id;
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

}

package com.javastudy;

public class ItemEx extends Item {

    private String name;

    public ItemEx(Long id) {
        super(id);
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

}

I expected to result below but actually not. I would like to know how to show the differences between two Collections. (objects are parent and child relationship)
In this case, can I use standard method like removeAll() or can you recommend another approach like using apache-commons. Thanks.

CONSTRAINT
------------------------------
1.Item.class is unmodifiable(eg. I can not add equals method)
2.If id is same between two objects, they are assumed as same things.
------------------------------

EXPECTED
------------------------------
removed object are:
2
same object are:
1
3
add object are:
4
------------------------------

ACTUAL
------------------------------
removed object are:
1
2
3
same object are:
add object are:
1
3
4
------------------------------

package com.javastudy;

import java.util.ArrayList;
import java.util.List;

public class CollectionCompareToObjects {

    public static void main(String[] args) {

        List<Item> before = new ArrayList<Item>();
        List<ItemEx> after = new ArrayList<ItemEx>();

        before.add(new Item(1L));
        before.add(new Item(2L)); // delete
        before.add(new Item(3L));

        after.add(new ItemEx(1L));
        after.add(new ItemEx(3L));
        after.add(new ItemEx(4L)); // added

        List<Item> removed = new ArrayList<Item>(before);
        removed.removeAll(after);

        System.out.println("removed objects are:");
        for(Item item : removed){
            System.out.println(item.getId());
        }

        List<Item> same = new ArrayList<Item>(before);
        same.retainAll(after);

        System.out.println("same objects are:");
        for(Item item : same){
            System.out.println(item.getId());
        }

        List<Item> added = new ArrayList<Item>(after);
        added.removeAll(before);

        System.out.println("add objects are:");
        for(Item item : added){
            System.out.println(item.getId());
        }

    }

}


package com.javastudy;

public class Item {

    private Long id;

    public Item(Long id) {
        this.id = id;
    }

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

}

package com.javastudy;

public class ItemEx extends Item {

    private String name;

    public ItemEx(Long id) {
        super(id);
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

}

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评论(1

怪我太投入 2024-10-15 10:33:09

Java 集合依赖于 equalshashCode 方法(后者由 HashMapHashSet 等使用)。

如果您希望能够使用 Java 集合的数据结构功能(例如 removeAllretainAll 等),您需要为对象提供 的正确实现>等于hashCode

如果您无法修改 Item 类,则可以使用自己的 equals 实现编写一个包装类:

public class ItemWrapper {
    private final Item item;
    public ItemWrapper(Item item) {
        this.item = item;
    }

    public Item getItem() {
        return item;
    }

    @Override
    public boolean equals(Object obj) {
        return obj instanceof ItemWrapper && item.getId().equals(((ItemWrapper) obj).item.getId());
    }

    @Override
    public int hashCode() {
        return item.getId().hashCode();
    }
}

为每个对象创建一个新的 ItemWrapper原始 Item,将 ItemWrapper 存储在 Java 集合中,并使用所需的方法 (removeAll/retainAll)。然后迭代生成的集合并通过调用每个 ItemWrappergetItem() 方法来检索 Item

您的另一个选择是子类化 ArrayList,但这似乎是一个更复杂的解决方案。

另一种选择是不使用 Java 集合来执行删除/保留逻辑,而是自己实现它们。

Java collections rely on the equals and hashCode methods (the latter is used by HashMaps, HashSets and others).

If you want to be able to use the data structure capabilities of Java collections (such as removeAll, retainAll etc.), you need to supply objects with proper implementations of equals and hashCode.

If you can't modify the Item class, you can write a wrapper class with your own implementation of equals:

public class ItemWrapper {
    private final Item item;
    public ItemWrapper(Item item) {
        this.item = item;
    }

    public Item getItem() {
        return item;
    }

    @Override
    public boolean equals(Object obj) {
        return obj instanceof ItemWrapper && item.getId().equals(((ItemWrapper) obj).item.getId());
    }

    @Override
    public int hashCode() {
        return item.getId().hashCode();
    }
}

Create a new ItemWrapper for each original Item, store the ItemWrappers in Java collections, and use the required methods (removeAll/retainAll). Then iterate over the resulting collection and retrieve the Items by calling each ItemWrapper's getItem() method.

Your other option is to subclass ArrayList, but it seems like a more convoluted solution.

Yet another option is not to use Java collections for the remove/retain logic, implementing them yourself instead.

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