检测文件是否重复，如果不重复则重命名
我有一些将文件移动到同一目录的代码。什么是一个好的策略：
- 检测文件是否与目录中现有文件重复？这是为了决定是删除源还是简单地保留它。
- 如果已存在同名但内容不同的目标文件，请重命名源文件？
I have some code that moves files to the same directory. What would be a good strategy to:
- Detect if a file is a duplicate of an existing file in the directory? This is to decide whether to delete the source or simply leave it.
- Rename the source file if a destination file with the same name but different content already exists?
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大多数编程语言都会有一个类似于 FileExists 的函数，它获取文件名并返回一个布尔值，指示文件系统上是否存在给定名称的文件。
计算两个文件的 SHA1 校验和并比较这些哈希值。大多数语言都会有一个 sha1 函数，它获取表示文件内容的字节数组，并返回表示 SHA1 哈希值的字节数组。
Most programming languages will have a function called something similar to
FileExiststaking a filename and returning a boolean indicating whether a file with the given name exists on the file system.Calculate a SHA1 checksum for both files and compare those hashes. Once again most languages will have a sha1 function taking an array of bytes representing the contents of the files and returning an array of bytes representing the SHA1 hash.
嗯，一个简单的方法是进行循环冗余检查。多种语言都有实现此功能的函数。您还可以计算文件的 md5 和。但这并不是 100% 可靠。
如果您需要检查它们是否相同，则需要打开两个文件的流，并逐字节比较它们。
重复文件名的检查很明显，比较一下。
编辑：如果您有很多文件，请比较文件大小。如果不匹配，则它们不能相等。
Well, an easy way to do it is to do a cyclic redundancy check. Several languages have functions for this implemented. You can also calculate the md5 sum for your files. This is not 100% reliable though.
If you need to check if they are IDENTICAL, you need to open up a stream to both files, and compare them byte by byte.
The check for duplicate filenames are obvious, compare them.
Edit: If you have many files, compare the file size. If it does not match, they cannot be equal.
如果您不需要原始文件名，作为一种方便的方法，只需计算文件“内容”的 MD5 或 SHA1 哈希值并将文件重命名为它即可。 :-)
If you don't need the original file names, as a handy way, just calculate MD5 or SHA1 hash of the file "content" and rename the file to it. :-)