策略模式问题-PHP
我有一个 Person 类，我想使用策略模式来添加存储行为。像这样
interface Storage{
public function store();
}
class LocalStorage implements Storage(){
public function store(){
..
// save in a file
..
}
}
class Person{
private $behaviourStorage;
private $name;
private $age;
public function __construct(Storage $objStorage,$name,$age) {
$this->behaviourStorage = $objStorage;
}
public function Store(){
$this->behaviourStorage->store();
}
}
$objPerson = new Person(new LocalStorage(),'John',32);
我的问题是，如何使用存储行为来保存对象 person 的信息？如何将对象传递到 LocalStorage 以便它知道要保存什么？
也许这毕竟不是正确的设计模式，但意图很明确：为 person 对象实现不同的存储行为。
I have a class Person and I would like using the Strategy pattern to add a storage behavior. Something like this
interface Storage{
public function store();
}
class LocalStorage implements Storage(){
public function store(){
..
// save in a file
..
}
}
class Person{
private $behaviourStorage;
private $name;
private $age;
public function __construct(Storage $objStorage,$name,$age) {
$this->behaviourStorage = $objStorage;
}
public function Store(){
$this->behaviourStorage->store();
}
}
$objPerson = new Person(new LocalStorage(),'John',32);
My question is, how can I use the storage behavior to save the information of the object person ? How do I pass the object to the LocalStorage so it knows what to save ?
Maybe this is not the right design pattern after all but the intent is clear : implement different storage behaviours for the person object.
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修改
Person::Store()以便它调用$this->behaviourStorage->store($this)，然后检查传递的对象中的字段到该方法，或者让它使用要存储的字段值调用$this->behaviourStorage->store()。Either modify
Person::Store()so that it calls$this->behaviourStorage->store($this), and then examine the fields in the object passed to that method, or have it call$this->behaviourStorage->store()with the field values to store.