.NET Micro Framework，在内存有限的设备上读取文件

发布于 2024-10-08 02:46:49 字数 248 浏览 8 评论 0原文

在 ChipworkX 设备上，我们将使用以下方式读取文件：

File.ReadAllBytes(filename);

但如果我们在内存量小得多的 NetDuino Plus 上尝试这样做，
我们只是得到一个 OutOfMemoryException 异常。

这些文件不是那么大，但我想在这种情况下这都是相对的（最大 1.5kb）。

在这样的设备上读取文件的正确方法是什么？

原文

On a ChipworkX device we would read files using:

File.ReadAllBytes(filename);

But if we try that on a NetDuino Plus which has a much smaller amount of memory,
we simply get an OutOfMemoryException.

The files are not that big, but I guess that's all relative in this case (1.5kb max).

What's the correct way to read files on a device like this?

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笛声青案梦长安 2024-10-15 02:46:49

使用 FileStream

using (var fileStream = new FileStream(filename, FileMode.Open))
{
    byte[] block = new byte[1024];
    int readLength;
    while ((readLength = fileStream.Read(block, 0, block.Length)) > 0)
    {
        Process(block, readLength);
    }
}

编写您自己的 处理方法。 1024 的块长度只是一个示例，一次读取尽可能大的块。您可以根据数据进行更改。

Use a FileStream

using (var fileStream = new FileStream(filename, FileMode.Open))
{
    byte[] block = new byte[1024];
    int readLength;
    while ((readLength = fileStream.Read(block, 0, block.Length)) > 0)
    {
        Process(block, readLength);
    }
}

write your own Process method. The block length of 1024 is just an example, read as big chunks as you can process at a time. You can vary that depending on the data.

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属性 2024-10-15 02:46:49

我假设您认为应该有足够的内存。如果是这样，我怀疑内部默认缓冲区大小会造成问题。尝试在打开文件时明确指定缓冲区大小，以使其紧贴实际文件长度：

string path = //some path
byte[] buffer;
int bufferSize = (int)new FileInfo(path).Length;

using (FileStream fs = new FileStream(
    path, FileMode.Open, FileAccess.Read, FileShare.Read, bufferSize))
{
    buffer = new byte[bufferSize];

    fs.Read(buffer, 0, buffer.Length);
}

//do stuff with buffer

I am assuming that you believe that there should be sufficient memory. If this is so, I suspect that internal default buffer sizes are blowing things. Try explicitly stating buffer sizes when opening the file to keep it tight to the actual file length:

string path = //some path
byte[] buffer;
int bufferSize = (int)new FileInfo(path).Length;

using (FileStream fs = new FileStream(
    path, FileMode.Open, FileAccess.Read, FileShare.Read, bufferSize))
{
    buffer = new byte[bufferSize];

    fs.Read(buffer, 0, buffer.Length);
}

//do stuff with buffer

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