如何释放 NSMutableArray 中的对象？
我有这个可变数组：
NSMutableArray *points = [pgroute getPoints:self];
其中[getPoint...]执行此操作：
{
NSMutableArray *normPoints = [[NSMutableArray alloc] init];
[normPoints addObject:@""];
[...]
return normPoints;
}
现在，
点是一个对象数组，对吗？
以这种方式释放 *points 数组是否正确？
for (int i = 0; i < [points count]; i++) {
[(NSString *)[points objectAtIndex:i] release];
}
[points release];
或者这是另一种正确的方法？
Xcode 编译器，使用 RUN_CLANG_STATIC_ANALYZER 告诉我有一个
引用的递减不正确 不被拥有的对象的计数 此时调用者
我该如何解决这个问题？
谢谢，
阿尔贝托.
i have this Mutable Array:
NSMutableArray *points = [pgroute getPoints:self];
where [getPoint...] do this:
{
NSMutableArray *normPoints = [[NSMutableArray alloc] init];
[normPoints addObject:@""];
[...]
return normPoints;
}
now,
points is an array of objects, right?
is correct to release *points array in this way?
for (int i = 0; i < [points count]; i++) {
[(NSString *)[points objectAtIndex:i] release];
}
[points release];
or it is another correct way?
Xcode compiler, with RUN_CLANG_STATIC_ANALYZER tell me there is an
Incorrect decrement of the reference
count of an object that is not owned
at this point by the caller
How can i resolve this?
thanks,
alberto.
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如果你想清空数组，只需这样做：
如果你想释放数组，你甚至可以跳过它并立即释放它：
数组将自行处理释放对象。再说一遍，如果您仅将
NSString文字（@"using this notation"）添加到数组中，则不需要释放它们，因为它们是常量。当然，这是一个不同的故事；我的观点是，NSMutableArray将在您需要时处理释放内容。If you want to empty the array, just do this:
If you want to release the array, you can even skip that and release it right away:
The array will handle releasing the objects on its own. Then again if you're only adding
NSStringliterals (@"using this notation") to the array, they don't need to be released since they are constants. That's a different story of course; my point is thatNSMutableArraywill deal with releasing stuff where necessary for you.