SQL - 与聚合混淆

发布于 2024-10-07 18:57:56 字数 344 浏览 0 评论 0原文

我目前有这个查询：

select
  customers.emailaddress,
  MAX(orders.orderdate) as "last order"
from orders
join customers
  on orders.customerID = customers.customerID
group by customers.emailaddress

这给了我电子邮件和最后订单日期。在“Orders”表中，有一个名为“PaymentTotal”的字段，如何根据 MAX(orders.orderdate) 返回的值获取该字段？（即我试图获取每封电子邮件的最后一个订单的金额）

原文

I currently have this query:

select
  customers.emailaddress,
  MAX(orders.orderdate) as "last order"
from orders
join customers
  on orders.customerID = customers.customerID
group by customers.emailaddress

Which gives me the emails, and the last order date. With the 'Orders' table, there is a field named 'PaymentTotal', how can I get this based on the value returned by MAX(orders.orderdate)? (ie am trying to get the amount of the last order per email)

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罪歌 2024-10-14 18:57:56

select c.EmailAddress, om.MaxOrderDate, o.PaymentTotal
from (
    select CustomerID, MAX(orders.orderdate) as MaxOrderDate
    from orders 
    group by CustomerID
) om
inner join orders o on om.CustomerID = o.CustomerID
    and om.MaxOrderDate = o.orderdate
inner join customers c on o.customerID = c.customerID

select c.EmailAddress, om.MaxOrderDate, o.PaymentTotal
from (
    select CustomerID, MAX(orders.orderdate) as MaxOrderDate
    from orders 
    group by CustomerID
) om
inner join orders o on om.CustomerID = o.CustomerID
    and om.MaxOrderDate = o.orderdate
inner join customers c on o.customerID = c.customerID

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