ORA-01843“不是有效的月份”和 ORA-01861“文字与格式字符串不匹配”

发布于 2024-10-07 18:13:40 字数 657 浏览 1 评论 0原文

SQL> select to_timestamp('2010-12-14:09:56:53') - to_timestamp('2010-12-14:09:56:46') from dua
l;
select to_timestamp('2010-12-14:09:56:53') - to_timestamp('2010-12-14:09:56:46') from dual
                    *
ERROR at line 1:
ORA-01843: not a valid month


SQL> select to_date('2010-12-14:09:56:53') - to_date('2010-12-14:09:56:46') from dual;
select to_date('2010-12-14:09:56:53') - to_date('2010-12-14:09:56:46') from dual
               *
ERROR at line 1:
ORA-01861: literal does not match format string

执行 a 的正确方法是什么?

2010-12-14:09:56:53
minus
2010-12-14:09:56:46

在 Oracle SQL 中

SQL> select to_timestamp('2010-12-14:09:56:53') - to_timestamp('2010-12-14:09:56:46') from dua
l;
select to_timestamp('2010-12-14:09:56:53') - to_timestamp('2010-12-14:09:56:46') from dual
                    *
ERROR at line 1:
ORA-01843: not a valid month


SQL> select to_date('2010-12-14:09:56:53') - to_date('2010-12-14:09:56:46') from dual;
select to_date('2010-12-14:09:56:53') - to_date('2010-12-14:09:56:46') from dual
               *
ERROR at line 1:
ORA-01861: literal does not match format string

What is the correct way to do a

2010-12-14:09:56:53
minus
2010-12-14:09:56:46

in Oracle SQL?

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(2

開玄 2024-10-14 18:13:40

您必须指定时间戳字符串的格式 <代码>TO_DATE< code>TO_TIMESTAMP 函数:

select 
    to_date('2010-12-14:09:56:53', 'YYYY-MM-DD:HH24:MI:SS') - 
    to_date('2010-12-14:09:56:46', 'YYYY-MM-DD:HH24:MI:SS') 
from dual;

结果将以天为单位,您可以将其乘以 86,400 以获得秒:

TO_DATE('2010-12-14:09:56:53','YYYY-MM-DD:HH24:MI:SS')-TO_DATE('2010-12-14:09:56
--------------------------------------------------------------------------------
.000081019

使用 TO_TIMESTAMP

select 
    to_timestamp('2010-12-14:09:56:53', 'YYYY-MM-DD:HH24:MI:SS') - 
    to_timestamp('2010-12-14:09:56:46', 'YYYY-MM-DD:HH24:MI:SS') 
from dual;

结果将采用 TIMESTAMP 格式:

TO_TIMESTAMP('2010-12-14:09:56:53','YYYY-MM-DD:HH24:MI:SS')-TO_TIMESTAMP('2
---------------------------------------------------------------------------
+000000000 00:00:07.000000000

You have to specify format that your timestamp string is in to TO_DATE and TO_TIMESTAMP functions:

select 
    to_date('2010-12-14:09:56:53', 'YYYY-MM-DD:HH24:MI:SS') - 
    to_date('2010-12-14:09:56:46', 'YYYY-MM-DD:HH24:MI:SS') 
from dual;

Result will be in days, which you can multiply by 86,400 to get seconds:

TO_DATE('2010-12-14:09:56:53','YYYY-MM-DD:HH24:MI:SS')-TO_DATE('2010-12-14:09:56
--------------------------------------------------------------------------------
.000081019

Using TO_TIMESTAMP:

select 
    to_timestamp('2010-12-14:09:56:53', 'YYYY-MM-DD:HH24:MI:SS') - 
    to_timestamp('2010-12-14:09:56:46', 'YYYY-MM-DD:HH24:MI:SS') 
from dual;

Result will be in TIMESTAMP format:

TO_TIMESTAMP('2010-12-14:09:56:53','YYYY-MM-DD:HH24:MI:SS')-TO_TIMESTAMP('2
---------------------------------------------------------------------------
+000000000 00:00:07.000000000
秋日私语 2024-10-14 18:13:40

使用 to_timesatmp

select TO_TIMESTAMP('2010-12-14:09:56:53',  'YYYY-MM-DD:HH24:MI:SS.FF') 
 - TO_TIMESTAMP('2010-12-14:09:56:46',  'YYYY-MM-DD:HH24:MI:SS.FF') 

from dual

Use to_timesatmp

select TO_TIMESTAMP('2010-12-14:09:56:53',  'YYYY-MM-DD:HH24:MI:SS.FF') 
 - TO_TIMESTAMP('2010-12-14:09:56:46',  'YYYY-MM-DD:HH24:MI:SS.FF') 

from dual
~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文