我如何将值从一种方法返回到另一种方法&交换

发布于 2024-10-07 17:05:19 字数 1187 浏览 8 评论 0原文

我有这个，

public class Mapper implements ScramblerIF
{
 private static String map = "drsjckpwrypwsftylmzxopqtdo";

public static String charAt(String str) 
{
 //char[] chars = str.toCharArray();
int length = str.length();

 for(int i=0; i<length; i++)
{
 char aChar = str.charAt(i);
 char upper = Character.toUpperCase(aChar);
 int num = (upper - 'A');
char mChar = map.charAt(num);
 //String chard = Character.toString(mChar);

 StringBuffer buf = new StringBuffer( str);
   buf.setCharAt( i, mChar );
 }
   return str;
 }

public String scramble(String str) {
return charAt(str);
 }
}

我试图将其到达该方法

 public String scramble(String str) {
return charAt(str);
 }

返回该方法的计算值的

 public static String charAt(String str)

位置。不知道我哪里错了。

另外，除了使用

StringBuffer buf = new StringBuffer( str);
   buf.setCharAt( i, mChar );

我如何能够使用交换功能？当我尝试时，

 char temp = chars[i];
chars[i] = chars[mChar];
chars[mChar] = temp;

我得到了 ArrayIndexOutOfBoundsException。我想做的总结是“对于原始字符串中的每个字符，使用其在字母表中的位置来查找其在映射字符串中的替换。例如，字符串“dog”将被翻译为“jtp”。 ”

原文

I have this

public class Mapper implements ScramblerIF
{
 private static String map = "drsjckpwrypwsftylmzxopqtdo";

public static String charAt(String str) 
{
 //char[] chars = str.toCharArray();
int length = str.length();

 for(int i=0; i<length; i++)
{
 char aChar = str.charAt(i);
 char upper = Character.toUpperCase(aChar);
 int num = (upper - 'A');
char mChar = map.charAt(num);
 //String chard = Character.toString(mChar);

 StringBuffer buf = new StringBuffer( str);
   buf.setCharAt( i, mChar );
 }
   return str;
 }

public String scramble(String str) {
return charAt(str);
 }
}

I am trying to get it to where the method

 public String scramble(String str) {
return charAt(str);
 }

returns the computed value from the

 public static String charAt(String str)

method. Don't know where i went wrong.

Also instead of using

StringBuffer buf = new StringBuffer( str);
   buf.setCharAt( i, mChar );

how would i be able to use the swap function?
When I try

 char temp = chars[i];
chars[i] = chars[mChar];
chars[mChar] = temp;

I am given an ArrayIndexOutOfBoundsException.
Summary of what i am trying to do is "For each character in the original string, use its position in the alphabet to look up its replacement in the map string. For example, the string “dog” would be translated to “jtp”."

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高冷爸爸 2024-10-14 17:05:19

此拼字游戏使用您提供的替换地图。它还处理大写和小写大小写字母：

public class Mapper {
    //                           abcdefghijklmnopqrstuvwxyz
    private static String map = "drsjckpwrypwsftylmzxopqtdo";

    public static String scramble(String str) {

        if (!str.matches("[A-Za-z]*"))
            throw new RuntimeException(str + " contains weird characters");

        String out = "";
        for (char c : str.toCharArray()) {
            if (Character.isUpperCase(c)) {
                out += Character.toUpperCase(map.charAt(c - 'A'));
            } else {
                out += map.charAt(c - 'a');
            }
        }

        return out;

    }

    public static void main(String[] args) {
        System.out.println(scramble("David"));
    }
}

This scrables with the replacement-map you have provided. It also handles upper and lower case letters:

public class Mapper {
    //                           abcdefghijklmnopqrstuvwxyz
    private static String map = "drsjckpwrypwsftylmzxopqtdo";

    public static String scramble(String str) {

        if (!str.matches("[A-Za-z]*"))
            throw new RuntimeException(str + " contains weird characters");

        String out = "";
        for (char c : str.toCharArray()) {
            if (Character.isUpperCase(c)) {
                out += Character.toUpperCase(map.charAt(c - 'A'));
            } else {
                out += map.charAt(c - 'a');
            }
        }

        return out;

    }

    public static void main(String[] args) {
        System.out.println(scramble("David"));
    }
}

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