如何访问特定 XMLnode 的innerText

发布于 2024-10-07 14:31:24 字数 1046 浏览 0 评论 0原文

你好我有以下 XML 片段：

  <Customer AccountNumber="4">
    <CustomerInfo>
      <firstName>Andrew</firstName>
      <lastName>Walker</lastName>
    </CustomerInfo>
    <Transactions>
      <AccountBalance>595848584.4</AccountBalance>
    </Transactions>
  </Customer>

来自一个更大的 XML 文件。我想访问 C# 中的。目前我正在执行以下操作：

    foreach (XmlNode customer in root)
    {
        i++;
        if(_AccNumber== Convert.ToInt32(customer.Attributes[0].Value))
        {
            searchNode = CustNodes[(i - 1)];
            string _firstName = searchNode.FirstChild.FirstChild.InnerText;

        }
    }

当我在调试器中查看 searchNode 时，我可以在结果视图元素 [0] 中看到它有一个 localName CustomerInfo 如您所料。因此，在调试器中，名字具有以下路径：

searchNode -> [0].[0].[0].value

这是否有意义？

有更好的方法吗？（没有 LINQ）？抱歉，如果有不清楚的地方……现在是凌晨 2:30！让我知道，我会更好地解释自己。谢谢！！

原文

Hi
I have the following XML fragment:

  <Customer AccountNumber="4">
    <CustomerInfo>
      <firstName>Andrew</firstName>
      <lastName>Walker</lastName>
    </CustomerInfo>
    <Transactions>
      <AccountBalance>595848584.4</AccountBalance>
    </Transactions>
  </Customer>

from a bigger XML file. I want to access the <firsName> in C#.
Currently I am doing the following:

    foreach (XmlNode customer in root)
    {
        i++;
        if(_AccNumber== Convert.ToInt32(customer.Attributes[0].Value))
        {
            searchNode = CustNodes[(i - 1)];
            string _firstName = searchNode.FirstChild.FirstChild.InnerText;

        }
    }

When I view searchNode in the debugger I can see in the results view element [0] which has a localName CustomerInfo as you expect. So in the debugger first name has the following path:

searchNode -> [0].[0].[0].value

if that makes sense?

Is there any better way of doing this? (without LINQ)?
Apologies, if something isn't clear....its 2:30AM! Let me know and I'll explain myself better.
Thanks!!

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

静谧幽蓝 2024-10-14 14:31:24

我认为 xpath 很难理解，所以最好使用 GetElementsByTagName 函数

XmlDocument doc = new XmlDocument();
        doc.Load(@"sample.xml");
        XmlNodeList firstNameNodes =  doc.GetElementsByTagName("firstName");
        foreach (XmlNode node in firstNameNodes)
        {
            string firstName =  node.InnerText;
        }

I think xpath is so much complex to understand , so better to use the GetElementsByTagName function

XmlDocument doc = new XmlDocument();
        doc.Load(@"sample.xml");
        XmlNodeList firstNameNodes =  doc.GetElementsByTagName("firstName");
        foreach (XmlNode node in firstNameNodes)
        {
            string firstName =  node.InnerText;
        }

回复收藏 0 原文

梦太阳 2024-10-14 14:31:24

尝试 XPath.. 像这样的东西应该可以工作：

string firstName = String.Empty;

var xmlNode = doc.SelectSingleNode(String.Format("//Customer[@AccountNumber='{0}']/CustomerInfo/firstName", _AccNumber));
if (xmlNode != null)
    firstName = xmlNode.InnerText;

Try XPath.. something like this should work:

string firstName = String.Empty;

var xmlNode = doc.SelectSingleNode(String.Format("//Customer[@AccountNumber='{0}']/CustomerInfo/firstName", _AccNumber));
if (xmlNode != null)
    firstName = xmlNode.InnerText;

回复收藏 0 原文

~没有更多了~