为现有查询选择最大值
首先,这是我的代码
SELECT dbo.tblPat.pID, dbo.tblRec.rID,
right(rPCheck, LEN(rPCheck) - (CHARINDEX('|', rPCheck))) as pCheck,
right(rGP, LEN(rGP) - (CHARINDEX('|', rGP))) as GPCheck
FROM
dbo.tblPat INNER JOIN
dbo.tblPatRecords ON dbo.tblPat.pID = dbo.tblPatRecords.pID INNER JOIN
dbo.tblRec ON dbo.tblPatRecords.rID = dbo.tblRec.rID
WHERE
(DATEPART(dw, dbo.tblRec.rDateRecAdd) IN (5, 6, 7))
AND (dbo.tblRec.rGP <> N'0')
AND (dbo.tblRec.rPCheck <> N'0')
AND right(rPCheck, LEN(rPCheck) - (CHARINDEX('|', rPCheck))) > right(rGP, LEN(rGP) - (CHARINDEX('|', rGP)))
ORDER BY dbo.tblPat.pID, dbo.tblRec.rID
,基本上以这种格式返回数据
39 366 26/06/2008 16:54:35 26/06/2008 15:04:53
39 368 27/06/2008 09:33:55 27/06/2008 08:57:07
39 369 27/06/2008 09:35:14 27/06/2008 08:57:07
39 370 27/06/2008 09:36:34 27/06/2008 08:57:07
39 371 27/06/2008 09:37:33 27/06/2008 08:57:07
39 372 27/06/2008 09:37:33 27/06/2008 08:57:07
39 373 27/06/2008 09:37:33 27/06/2008 08:57:07
39 374 27/06/2008 09:37:33 27/06/2008 08:57:07
*39 397 27/06/2008 13:13:49 27/06/2008 12:48:25*
92 46310 19/08/2008 15:52:50 03/10/2008 14:50:00
92 46313 19/08/2008 15:52:50 03/10/2008 14:52:50
92 46315 19/08/2008 15:52:50 03/10/2008 14:52:50
92 46558 19/08/2008 15:52:50 03/10/2008 19:26:04
92 46559 19/08/2008 15:52:50 03/10/2008 19:26:04
92 46623 04/10/2008 10:46:39 03/10/2008 19:26:04
*92 46632 04/10/2008 10:46:39 03/10/2008 19:26:04*
正如您可能已经猜到的那样,我需要为每个 PID 选择最后一个条目,所以在这种情况下,我需要
39 397 27/06/2008 13:13:49 27/06/2008 12:48:25
92 46632 04/10/2008 10:46:39 03/10/2008 19:26:04
任何帮助都会很棒。我可以作弊并将其变成一个视图,然后再做另一个视图,但我想尽可能干净
firstly, here's my code
SELECT dbo.tblPat.pID, dbo.tblRec.rID,
right(rPCheck, LEN(rPCheck) - (CHARINDEX('|', rPCheck))) as pCheck,
right(rGP, LEN(rGP) - (CHARINDEX('|', rGP))) as GPCheck
FROM
dbo.tblPat INNER JOIN
dbo.tblPatRecords ON dbo.tblPat.pID = dbo.tblPatRecords.pID INNER JOIN
dbo.tblRec ON dbo.tblPatRecords.rID = dbo.tblRec.rID
WHERE
(DATEPART(dw, dbo.tblRec.rDateRecAdd) IN (5, 6, 7))
AND (dbo.tblRec.rGP <> N'0')
AND (dbo.tblRec.rPCheck <> N'0')
AND right(rPCheck, LEN(rPCheck) - (CHARINDEX('|', rPCheck))) > right(rGP, LEN(rGP) - (CHARINDEX('|', rGP)))
ORDER BY dbo.tblPat.pID, dbo.tblRec.rID
Whih basicallybrings back data in this format
39 366 26/06/2008 16:54:35 26/06/2008 15:04:53
39 368 27/06/2008 09:33:55 27/06/2008 08:57:07
39 369 27/06/2008 09:35:14 27/06/2008 08:57:07
39 370 27/06/2008 09:36:34 27/06/2008 08:57:07
39 371 27/06/2008 09:37:33 27/06/2008 08:57:07
39 372 27/06/2008 09:37:33 27/06/2008 08:57:07
39 373 27/06/2008 09:37:33 27/06/2008 08:57:07
39 374 27/06/2008 09:37:33 27/06/2008 08:57:07
*39 397 27/06/2008 13:13:49 27/06/2008 12:48:25*
92 46310 19/08/2008 15:52:50 03/10/2008 14:50:00
92 46313 19/08/2008 15:52:50 03/10/2008 14:52:50
92 46315 19/08/2008 15:52:50 03/10/2008 14:52:50
92 46558 19/08/2008 15:52:50 03/10/2008 19:26:04
92 46559 19/08/2008 15:52:50 03/10/2008 19:26:04
92 46623 04/10/2008 10:46:39 03/10/2008 19:26:04
*92 46632 04/10/2008 10:46:39 03/10/2008 19:26:04*
As you may have guessedm I need to pick out the last entry for each pID so in this case, I need
39 397 27/06/2008 13:13:49 27/06/2008 12:48:25
92 46632 04/10/2008 10:46:39 03/10/2008 19:26:04
Any help would be great. I could cheat and turn this into a view and then do another view but I want to be as clean as possible
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不要直接 JOIN 到 tblPatRecords,而是尝试用子查询的联接替换,例如将 FROM 子句替换为:
Instead of the JOIN onto tblPatRecords directly, try replacing with a join onto a subquery, so e.g. replace your FROM clause to this:
如果您使用的是 SQL Server 2005 或 2008,则可以使用 ROW_NUMBER 函数。试试这个:
If you are using SQL Server 2005 or 2008, then you can use the ROW_NUMBER function. Try this: