flex bitmapData 绘制 - 如何设置在哪里绘制

发布于 2024-10-07 13:05:59 字数 505 浏览 7 评论 0原文

我有一个类，它创建一个带有合并 2 个 IBitmapDrawable 的 bitmapData 的类。其中一个是 24*20，另一个是 16*16。我想在 bitmapData 对象中先绘制较小的，其宽度和高度为 24*20 但我想把它画在大边界的中心。

有谁知道该怎么做？谢谢...

if (baseIcon) {
    var result:BitmapData = new BitmapData(baseIconWidth,baseIconHeigt,true, 0x00FFFFFF);
    result.draw(baseIcon,new Matrix(1, 0, 0, 1, 0, 0));
    if (indicatorIcon) {
       result.draw(indicatorIcon,new Matrix(1, 0, 0, 1, 0, 0));
    }
    bitmapData = result;
    baseIcon = null;            
}

原文

i have a class thats create a class with bitmapData that merge 2 IBitmapDrawable.
one of them is 24*20 while the other is 16*16.
i want to draw the smaller first in a bitmapData object which its width and height are 24*20
but i want to draw it in the center of the big bounds.

does anyone know's how to do that?
thanks...

if (baseIcon) {
    var result:BitmapData = new BitmapData(baseIconWidth,baseIconHeigt,true, 0x00FFFFFF);
    result.draw(baseIcon,new Matrix(1, 0, 0, 1, 0, 0));
    if (indicatorIcon) {
       result.draw(indicatorIcon,new Matrix(1, 0, 0, 1, 0, 0));
    }
    bitmapData = result;
    baseIcon = null;            
}

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寂寞美少年 2024-10-14 13:05:59

试试这个：

if (baseIcon) {
    var result:BitmapData = new BitmapData(baseIconWidth,baseIconHeigt,true, 0x00FFFFFF);
    var m:Matrix = new Matrix();
    m.translate(baseIconWidth/2 - baseIcon.width/2,baseIconHeight/2 - baseIcon.height/2);
    result.draw(baseIcon,m);
    if (indicatorIcon) {
       result.draw(indicatorIcon,new Matrix(1, 0, 0, 1, 0, 0));
    }
    bitmapData = result;
    baseIcon = null;            
}

Try this:

if (baseIcon) {
    var result:BitmapData = new BitmapData(baseIconWidth,baseIconHeigt,true, 0x00FFFFFF);
    var m:Matrix = new Matrix();
    m.translate(baseIconWidth/2 - baseIcon.width/2,baseIconHeight/2 - baseIcon.height/2);
    result.draw(baseIcon,m);
    if (indicatorIcon) {
       result.draw(indicatorIcon,new Matrix(1, 0, 0, 1, 0, 0));
    }
    bitmapData = result;
    baseIcon = null;            
}

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